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olasank [31]
4 years ago
15

Part A: Solve A = (x + 23) for x. (4 points) Part B: Determine the value of x when A = 108. (2 points) Part C: Solve -np - 90 &g

t; 30 for n. Show your work. (4 points)
Mathematics
1 answer:
Galina-37 [17]4 years ago
7 0
<span>Part A: Solve A = (x + 23) for x.

A = x + 23

=> A - 23 = x + 23 - 23

=> A - 23 = x

=> x = A - 23 <------- answer

Part B: Determine the value of x when A = 108

Replace the value of A in the expression x = A - 23

x = 108 - 23 = 75

x = 75 <------- answer

Part C: Solve -np - 90 > 30 for n.

-np - 90 > 30

=> -np + np - 90 >30 +  np

=> - 90 > 30 + np

=> -90 - 30 > 30 - 30 + np

=> -120 > np

=> np < - 120 <----- answer
</span>
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Answer:

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The amount with Ethan = $8.421

Step-by-step explanation:

Let the Initial amount with Dakota be 'x'

Therefore,

Amount with Ethan = x + $8

After giving \frac{1}{4} of money to the Dakota i.e \frac{1}{4} of ( x + $8)

Amount available with Dakota = x + [\frac{1}{4}\times(x+8)]

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Amount available with Ethan = (x + $8) - [\frac{1}{4}\times(x+8)]

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Now,

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6x + 48 = 25x + 40

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The amount with Dakota = $0.421

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= $0.421 + $8

= $8.421

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