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olasank [31]
3 years ago
15

Part A: Solve A = (x + 23) for x. (4 points) Part B: Determine the value of x when A = 108. (2 points) Part C: Solve -np - 90 &g

t; 30 for n. Show your work. (4 points)
Mathematics
1 answer:
Galina-37 [17]3 years ago
7 0
<span>Part A: Solve A = (x + 23) for x.

A = x + 23

=> A - 23 = x + 23 - 23

=> A - 23 = x

=> x = A - 23 <------- answer

Part B: Determine the value of x when A = 108

Replace the value of A in the expression x = A - 23

x = 108 - 23 = 75

x = 75 <------- answer

Part C: Solve -np - 90 > 30 for n.

-np - 90 > 30

=> -np + np - 90 >30 +  np

=> - 90 > 30 + np

=> -90 - 30 > 30 - 30 + np

=> -120 > np

=> np < - 120 <----- answer
</span>
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In a class of 147 students, 95 are taking math(m), 75 are taking science (s), 52 are taking both math and science. What is the p
Dmitriy789 [7]
Subtract 52 from m, s, and the total amount of students.. 52 is the amount of students that would take both math and science. m now equals 43, s now equals 23, and the total students remaining is 95.

Since the criteria wants you to exclude students that take math or science, add m and s together. 

43 + 23 = 66

This is the total amount of students that take math or science.

To find the probability of picking a student that doesn't take math or science, subtract 66 from the total amount of students. 

95 - 66 = 29

Take this amount and divide by the total amount of students again.

\frac{29}{95} = 0.3052

Convert the decimal into a percentage.

0.3052 = 30.52 %

There is a 30.52% chance of picking a student that doesn't take math nor science.
6 0
3 years ago
Are the two triangles similar? how do you know?
Likurg_2 [28]

Answer:

A. no

Step-by-step explanation:

You might expect to use SAS in showing similarity, but the sides on either side of congruent angles M are in the ratio of 3:4 in one triangle and 2:3 in the other. Corresponding sides do not have the same ratio, so the triangles cannot be similar.

4 0
3 years ago
The diagram shows the cross-section of a wall of a cinema.
Anna71 [15]

Answer:

  • 280 m²
  • £133

Step-by-step explanation:

The area of the wall is the sum of the areas of the different sections of the wall. The cost to paint it will be the product of the cost of a tin of paint and the number of tins required.

__

Here, the shape of the wall can be divided into two trapezoids and a rectangle. Each shape has a corresponding area formula. Left-to-right, their areas are ...

<u>Left Trapezoid</u>

  A = 1/2(b1 +b2)h

  A = 1/2(10 m +11 m)(4 m) = 42 m²

<u>Middle Rectangle</u>

  A = LW

  A = (13 m)(11 m) = 143 m²

<u>Right Trapezoid</u>

  A = 1/2(b1 +b2)h

  A = 1/2(11 m +8 m)(10 m) = 95 m²

<u>Wall Area</u>

The total area to be painted is the sum of the above areas:

  total area = 42 m² +143 m² +95 m² = 280 m²

The area that needs to be painted is 280 m².

__

A tin of paint covers 15 m², so the number of tins needed is ...

  (15 m²)t = 280 m²

  t = 280/15 = 18 2/3 . . . . . . divide by the coefficient of t

We can only buy whole tins, so we need to buy 19 tins. Their cost will be ...

  (£7 /tin)(19 tins) = £133

It will cost £133 to paint the wall.

7 0
2 years ago
The price of a theater ticket increased from $7.50 to $7.75. the theater sold 315 tickets at the higher price. with the price in
Karolina [17]
7.50 X 315 =2362.50 at the lower price
7.75 X 315 = 2441.25 at the higher price



subtract 2362.50 from 2441.25 you get 78.75
3 0
3 years ago
Which reason justifies step 2 in the proof
tigry1 [53]
<h3>Answer: C. If two lines are parallel, then the alternate interior angles formed are congruent.</h3>

This is through the alternate interior angles theorem. Angles Q and T pair up as one alternate interior set of angles that are the same measure. The same thing applies to angles X and R.

The identical arrow markers on segments XQ and TR show that those segments are parallel. Segment TQ is one transversal cut (forming alternate interior angles Q and T). Segment XR is the other transversal cut (forming alternate interior angles X and R).

We could say "angle XRT" or "angle TRX" instead of "angle R", though its ideal to use shortcuts whenever possible. The same applies for the other angles as well.

6 0
3 years ago
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