3 years ago

What is the zeros of function of f(x)=2x+2

1 answer:

6 0

The answer is there !!!

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Nookie1986 [14]

Answer:

the mid point formula for this is x+x/2 and y+y/ 2 so #9would be 1/2, 3/2

7 0

2 years ago

zloy xaker [14]

The answer is 4! lol

4 0

3 years ago

rusak2 [61]

Nansjsjsjsjkakskskskalsso is not the

7 0

3 years ago

exis [7]

ANSWER

The vertex is (1,-3)

EXPLANATION

The given parabola has equation:

${y}^{2} + 6y + 8x + 1 = 0$

We group the variables to obtain:

${y}^{2} + 6y = - 8x - 1$

We complete the square to get,

${y}^{2} + 6y + {3}^{2} = - 8x - 1 + {3}^{2}$

${(y+ 3)}^{2} = - 8x +8$

${(y+ 3)}^{2} = - 8(x -1)$

The vertex is of the parabola is (1,-3)

7 0

3 years ago

iris [78.8K]

The function is increasing on the intervals
x ∈ (-∞, -1) ∪ (1, ∞)

5 0

3 years ago

What is the zeros of function of f(x)=2x+2​