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vovangra [49]
3 years ago
6

Steven has some money if he spends 9.00,then he will have three over five of the amount he started with

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0

what does the question want me to answer? tell me that and I can help you

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what is 3.73/33.46? the question is jose bought a magazine for 3.73 and some light bulbs for 4.78. he spent a total of 37.19. ho
bekas [8.4K]

Answer:

He bought 7 lightbulbs.

Step-by-step explanation:

37.19 - 3.73 = 33.46

33.46/4.78=7

3 0
3 years ago
Use greatest common factor and the distributive property to write an equivalent expression in factored form for the following Ex
aksik [14]
To solve this find the common number that can be divided by both and use that number.

In this case, 4 is divisible by both 4 and 12, and thus the final expression would be

4(d + 3e).

8 0
3 years ago
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19-20<br> Please<br><br> Thank u
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19-20 = -1 u have to subtract left from tight <span />
7 0
3 years ago
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A stick 1 meter long casts a shadow 0.6 meters long. A building casts a shadow 25 meters long. How tall is the building (to 2 de
zloy xaker [14]

Answer:

41.67

Step-by-step explanation:

Using the tangent on the stick with shadow:

tan(θ) = \frac{1}{0.6}

Using the tangent on the building:

tan(θ) = \frac{h}{25}

⇒ h = 25 · tan(θ)

       = 25 · \frac{1}{0.6}

⇒ h = 41.66... ≈ 41.67

8 0
3 years ago
Fill in the missing statement and reason in the proof of the Alternate Exterior Angles Theorem.
ludmilkaskok [199]

Answer:

∠EGB and ∠AGF are congruent;

Transitive Property of Equality

Step-by-step explanation:

The vertical angles theorem is about the angles that are opposite to each other. These angles are formed when two lines cross each other

Vertical angles are congruent i.e their measures are equal

Look at the attached graph

Given:

AB // CD

E , G , H , F are col-linear

The line which contains points E , G , H , F is a transversal for the parallel lines AB and CD

∵ AB and EF intersected at point G

∴ m∠EGB = m∠AGF ⇒ by the vertical angles theorem

When lines AB and EF intersected at G they formed opposite angles like angles EGB and AGF, then angles EGB and AGF are congruent (  vertical angle theorem)

∵ AB // CD and EF is a transversal

∴ m∠AGF = m∠CHF (corresponding angles theorem)

Transitive Property of Equality:  if one angle is equal to two other angles, then the two other angles are equal

 Therefore, If a = b and b = c, then a = c

∵ m∠EGB = m∠AGF

∵ m∠AGF = m∠CHF

∴ m∠EGB = m∠CHF (transitive property theorem)

 ∠EGB and ∠AGF are congruent; Transitive Property of Equality

4 0
3 years ago
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