Option( c ) is the correct one.
-2x +y= -3
x= (3+y)/2
By executing the value in second equation
{-(3+y)/2} +2y =3
( -3-y +4y)/2 =3
-3 +3y =6
3y = 9
y = 3
Again by substituting the value of y in any of the equation
-2x +y =-3
-2x =-6
x= 3.
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>