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2 years ago

8

Helpppppp :((((( this is confusing

2 answers:

lana66690 [7]2 years ago

7 0

It is G, because all the other charts are not equivalent to nearly 30% mowed

pav-90 [236]2 years ago

4 0

I’m not exactly sure but I think it is G

You might be interested in

1. Use the Law of Levers to solve the problem, x1y1=x2y2.

Mademuasel [1]

1) Never heard of someone referring to the Law of Levers before, must be showing my age. A system as you describe is at equilibrium when the net torque is equal to zero. Since torque is Fr=mgr so for this system we have a sum of:

27g*10+30g*x=0 The sum must be zero to be at equilibrium, dividing both sides by g you have:

270+30x=0

270=-30x

x=-9

The negative just indicates that the magnitude of 9 is on the opposite side of the fulcrum, so x=9ft in magnitude.

2) Inverse variation is of the form y=k/x, in this case we are given a point so we can solve for the constant, k, of variation...

y=k/x, and we are given y=-12 when x=5 so

-12=k/5

k=-60 so the equation is:

y=-60/x which can be expressed as

xy=-60

5 0

3 years ago

A mixture of green paint requires 3/4 pint yellow paint and 2/5 pint blue paint. How many pints of yellow paint will be needed i

katrin2010 [14]

Answer:

$1\frac{7}{8}$

Step-by-step explanation:

Given:

A mixture of green paint requires 3/4 pint yellow paint and 2/5 pint blue paint.

Question asked:

How many pints of yellow paint will be needed if the mixture contains one pint of blue paint ?

Solution:

We will easily find quantity of yellow paint, will be needed in the mixture, contains one pint of blue paint by using unitary method:

By using $\frac{2}{5} \ pint$ blue paint, yellow paint requires = $\frac{3}{4} \ pint$

By using 1 pint blue paint, yellow paint requires = $\frac{3}{4} \div\frac{2}{5} \\$

$=\frac{3}{4} \times\frac{5}{2} \\\\ =\frac{15}{8} \\\\ =1\frac{7}{8} \ pint$

Thus, $1\frac{7}{8}$ pint yellow paint requires in the mixture with one pint of blue paint.

4 0

3 years ago

HELP ASAP its due today<br> also please include the work if possible

castortr0y [4]

Use photomath. it shows the work too

6 0

3 years ago

AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to AB?

KiRa [710]

Answer:

C. -5x − 3y = 0

Step-by-step explanation:

A(-3, 0) and B(-6, 5)

First we find the slope of line AB

$slope = \frac{y_2-y_1}{x_2-x_1} =\frac{5-0}{-6+3} =\frac{-5}{3}$

Slope of the line parallel to AB = slope of line AB

When the lines are parallel then their slope are equal

So the slope of line parallel to AB = $\frac{-5}{3}$

The line passes through the origin (0,0)

Use equation y-y1= m (x-x1)

m = -5/3 , x1=0 and y1=0

$y-0 = \frac{-5}{3}(x-0)$

$y= \frac{-5}{3}(x)$

multiply the whole equation by 3

3y = -5x

Subtract 3x from both sides

0=-5x-3y

-5x - 3y =0

8 0

3 years ago

Find the intersection x>1 and x>5

Bond [772]

It would be 6 unless there is a line with a certain angle.

7 0

3 years ago