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3 years ago

10

Polynomials with the same roots can have different graphs. True? Or false?

1 answer:

Diano4ka-milaya [45]3 years ago

8 0

True.

E.g. (x-1)(x-2) versus 100(x-1)(x-2)

They have same roots of x= 1 or 2, but the second equation is 100 times stretching of the first one vertically

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4 years ago

What's 34 to the 9th power?

irinina [24]

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3 years ago

Please help me and explain how to do it

STALIN [3.7K]

Answer:

<A = 50

Step-by-step explanation:

The sum of the angles of a triangle are 180

<A + <B + <C = 180

2x-10 + 70 + x+30 = 180

Combine like terms

3x +90 = 180

Subtract 90 from each side

3x+90-90 = 180-90

3x= 90

Divide each side by 3

3x/3 =90/3

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5 0

4 years ago

Use differentiation method to find the slope of the tangent hence the

dezoksy [38]

Answer:

The equation of the tangent at x=-6 is $y=-\frac{3}{4}x-\frac{15}{2}$

Step-by-step explanation:

The equation of a circle with center (h,k) with radius r units is given by:

$(x-h)^2+(y-k)^2=r^2$

The given circle has center (-3,1) and radius 5 units.

We substitute the center and the radius into the equation to get;

$(x--3)^2+(y-1)^2=5^2$

$(x+3)^2+(y-1)^2=25$

To find the slope, we differentiate implicitly to get:

$2(x+3)+2(y-1)\fra{dy}{dx}=0$

$2(y-1)\frac{dy}{dx}=-2(x+3)$

$\frac{dy}{dx}=-\frac{x+3}{y-1}$

When x=-6;we have $(-6+3)^2+(y-1)^2=25$

$\implies 9+(y-1)^2=25$

$\implies (y-1)^2=25-9$

$\implies (y-1)^2=16$

$\implies y-1=\pm \sqrt{16}$

$\implies y-1=\pm4$

$\implies y=1\pm4$

$y=-3$ or $y=5$

From the graph the reuired point is (-6,-3).

We substitute this point to find the slope;

$\frac{dy}{dx}=-\frac{-6+3}{-3-1}$

$\frac{dy}{dx}=-\frac{3}{4}$

The equation is given by $y-y_1=m(x-x_1)$ .

We plug in the slope and the point to get:

$y--3=-\frac{3}{4}(x--6)$

$y=-\frac{3}{4}(x+6)-3$

$y=-\frac{3}{4}x-\frac{9}{2}-3$

$y=-\frac{3}{4}x-\frac{15}{2}$

5 0

4 years ago