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Len [333]
3 years ago
13

(x-3)^2/(x+1)(x-2)>0

Mathematics
1 answer:
Oduvanchick [21]3 years ago
3 0
\frac{(x - 3)^{2}}{(x + 1)(x - 2)} > 0

\frac{(x - 3)(x - 3)}{(x + 1)(x - 2)} > 0

\frac{x^{2} - 3x - 3x + 9}{x^{2} - 2x + x - 2} > 0

\frac{x^{2} - 6x + 9}{x^{2} - x - 2} > 0
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What does the following equal? Please help me!
Juli2301 [7.4K]

Answer:

the first answer

Step-by-step explanation:

1/8 of the absolute value is 1/8 positive

anything from the absolute value is positive because absolute value is the value of how far away the number is from zero.

3 0
3 years ago
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The cost of a car is $15,570. You plan to make a down payment of $1,500, and a monthly payment of $388.08 for 60 months.
sergiy2304 [10]
1. 15.570-1500= 14070. Yes it is B

7 0
3 years ago
Is 1/4 greater than, less than or equal to 2/3<br>​
Romashka-Z-Leto [24]

Answer:

Less than

Step-by-step explanation:

1/4 = 0.25 and 2/3 is approximately 0.67 so 1/4 is less than 2/3

8 0
3 years ago
Read 2 more answers
Given: 1; -5; -13 ; -23 ; ...<br><br> Derive a formula for the nth term in the pattern.
mylen [45]

Answer:

  f(n) = -n^2 -3n +5

Step-by-step explanation:

Suppose the formula is ...

  f(n) = an^2 +bn +c

Then we have ...

  f(1) = 1 = a(1^2) +b(1) +c

  f(2) = -5 = a(2^2) +b(2) +c

  f(3) = -13 = a(3^2) +b(3) +c

__

Here's a way to solve these equations.

Subtract the first equation from the second:

  -6 = 3a +b . . . . . 4th equation

Subtract the second equation from the third:

  -8 = 5a +b . . . . . 5th equation

Subtract the fourth equation from the fifth:

  -2 = 2a

  a = -1

Then substituting into the 4th equation to find b, we have ...

  -6 = 3(-1) +b

  -3 = b

and ...

  1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation

  5 = c

The formula is ...

  f(n) = -n^2 -3n +5

3 0
4 years ago
If f'(x) = 12x^3 - 2x^2 - 17 and f(1) = 8 , find f(x).
Cloud [144]

Answer:

f(x) =  3x⁴ - \frac{2X^{3} }{3} - 17x +  \frac{68}{3}

Step-by-step explanation:

To find f'(x), we will follow the steps below:

We will start by integrating both-side of the equation

∫f'(x) = ∫(12x^3 - 2x^2 - 17)dx

f(x)  = 3x⁴ - \frac{2X^{3} }{3} - 17x + C

Then we go ahead and find C

f(1) = 8

so we will replace x by 1 in the above equation and solve for c

f(1)  = 3(1)⁴ - \frac{2(1)^{3} }{3} - 17(1) + C

8 = 3 - \frac{2}{3} - 17 + C

C =8 - 3 + 17 + \frac{2}{3}

C = 22 +  \frac{2}{3}

C =\frac{66 + 2}{3}

C = \frac{68}{3}

f(x) =  3x⁴ - \frac{2X^{3} }{3} - 17x +  \frac{68}{3}

7 0
4 years ago
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