Question

Graph a parabola whose vertex is at (3,5)(3,5)left parenthesis, 3, comma, 5, right parenthesis with yyy-intercept at y=1y=1y, equals, 1.

Answer 1

Using the given information we found that the equation of the parabola is:

y = (-4/9)*(x - 3)^2 + 5

And its graph is below.

How to get the equation of the parabola?

For a parabola with vertex (h, k), the equation is:

y = a*(x - h)^2 + k

Here the vertex is (3, 5), so the equation is:

y = a*(x - 3)^2 + 5

And the y-intercept is y = 1, this means that:

1 = a*(0 - 3)^2 + 5

1 = a*9 + 5

1 - 5 = a*9

-4/9 = a

So the parabola is:

y = (-4/9)*(x - 3)^2 + 5

And its graph is below.

If you want to learn more about parabolas, you can read:

brainly.com/question/1480401