Graph a parabola whose vertex is at (3,5)(3,5)left parenthesis, 3, comma, 5, right parenthesis with yyy-intercept at y=1y=1y, eq
1 answer:
Using the given information we found that the equation of the parabola is:
y = (-4/9)*(x - 3)^2 + 5
And its graph is below.
<h3>How to get the equation of the parabola?</h3>
For a parabola with vertex (h, k), the equation is:
y = a*(x - h)^2 + k
Here the vertex is (3, 5), so the equation is:
y = a*(x - 3)^2 + 5
And the y-intercept is y = 1, this means that:
1 = a*(0 - 3)^2 + 5
1 = a*9 + 5
1 - 5 = a*9
-4/9 = a
So the parabola is:
y = (-4/9)*(x - 3)^2 + 5
And its graph is below.
If you want to learn more about parabolas, you can read:
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Answer:
The graphs of the two function will not intersect.
Step-by-step explanation:
We are given a quadratic function f(x).
Also g(x) is given by a set of values as:
x g(x)
1 -1
2 0
3 1
As g(x) is a linear function hence we find out the equation of g(x) by the slope intercept form of a line: y=mx+c
let g(x)=y
when x=1 , g(x)=-1
-1=m+c----(1)
when x=2 , g(x)=0
0=2m+c------(2)
Hence, on solving (1) and (2) by method of elimination we get:
m=1 and c=-2
Hence, the equation of g(x) is:
g(x)=x-2
So clearly from the graph we could see that the graph of the two functions will never intersect.
