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BartSMP [9]
3 years ago
12

Amy has 20 quarters. Sodas cost $0.75. Write an expression for how many quarters Amy has left after buying d amount of sodas.

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0
20-3d
tigjungfngvbjdenfg
ignore that^
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14. The area of 10 square plots is 160 ares. Find the length in metres of the side of each plot (3mks)​
VashaNatasha [74]

Answer:

Step-by-step explanation:

1 are = 100 m²

Assuming the ten squares are congruent, the area of each square is 160/10 = 16 are

16 are × 100 m²/are = 1600 m²

each side is √1600 = 40 m

7 0
3 years ago
The population of a city decreases by 1.2% per year. If this year's population is 177,000, what will next year's population be,
Vsevolod [243]

Answer:

Initial value

177000

Final value

174,876

Decrease

1.2%

Difference

-2,124

5 0
2 years ago
What value of B will make the product equal of 17 in the following expression: 17xb/7
Katyanochek1 [597]

The value B is 7. If we apply B=7 the answer is 17 for the expression 17×\frac{b}{7}

Step-by-step explanation:

            The given expression is 17×\frac{b}{7}  

Step:1

            Form an equation from given data,

            17×\frac{b}{7}= 17..............................(1)

                                                         (∵ product equal to 17)

Step:2

            Check for alternatives by apply the value of B in eqn (1)

            Assume be value of B for check the equation

            B=1

            Equation becomes,

            17×\frac{1}{7} = 2.4286 ≠ 17

            Take, B=2,

            17×\frac{2}{7} = 4.8571 ≠ 17

            Take, B=3,

            17×\frac{3}{7} = 7.2857 ≠ 17

similarly,

            B=7,

            17×\frac{7}{7} = 17                       (∵ The product equals to 17)

Result:

         So, the answer for B is 7.

7 0
4 years ago
Read 2 more answers
Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining
Flura [38]

Answer:

the equation should be corrected to fit the data of the problem.  With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams  → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years  → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

5 0
3 years ago
What is the value of x in the equation 8x – 2y = 48, when y = 4?
luda_lava [24]

Answer:

7

Step-by-step explanation:

8x-2y=48, replace y with 4, 8x-2(4)=48, multiply, 8x-8=48, add 8 to both sides to remove the -8, 8x=56 and finally divide by 8 to remove 8 from x, x=7.

8 0
3 years ago
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