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Sonja [21]
3 years ago
6

Please answer the question. (Giving Brainliest To However Answers Good)

Mathematics
1 answer:
Arisa [49]3 years ago
5 0

Answer:

100

Step-by-step explanation:

So in this problem, we have 5 base 10 blocks and 50 ones.

To find out the product we have to count by tens:

10, 20, 30, 40, 50

So 5 base 10 blocks = 50

Now we add the base ten blocks and the ones together:

50 + 50 = 100

So the answer is 100

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If ξ={1 , 2 , 3 , . . . , 8 , 9 , 10}
DENIUS [597]

Answer:

{1,4}

Step-by-step explanation:

A={3,6,9}

B={2,3,5,7}

C={1,2,3,4,5}

AUB={2,3,5,6,7,9}

(AUB)'={1,4,8,10}

(AUB)'⋂C={1,4}

7 0
3 years ago
Read 2 more answers
WHAT IS THE BENEFIT OF A "SPACE CUSHION" AROUND YOUR VEHICLE?
sweet-ann [11.9K]
A space cushion is a certain amount of distance you keep between u and the car in front of u that allows u to easily maneuver in any condition. The benefit would be : if another driver makes a mistake, ur space cushion gives u time to react.
4 0
3 years ago
In the diagram below, AC is perpendicular to BD. Find the value of N.
timurjin [86]
Hi there!

In order to find the value of N, we'll need to set the value of the angle containing the variable n equal to 90. This is because in perpendicular lines, all angles are equal to 90.

WORK:
5n - 25 = 90
5n = 115
n = 23
8 0
3 years ago
Help please asappppppppp​
Aleonysh [2.5K]

Answer:

First Equation: 6a-23

Second Equation: 5a-20

Step-by-step explanation:

So, I think you want me to answer part 2...

For the first equation, we can see that the denominator stays the exact same, meaning the numerator will also not change.

For the second equation, we can see the denominator changed from a-3 to 5a-15. The denominator was simply multiplied by 5. Since the denominator was multiplied by five we must multiply the numerator by five as well.

5(a-4)

5a-20

Hope this helps :)

3 0
2 years ago
PLEASE HELP!!!!!!!
andre [41]

Answer:

\frac{4^{21}}{5^6}

Step-by-step explanation:

\left(\frac{4^7}{5^2}\right)^3

=\frac{\left(4^7\right)^3}{\left(5^2\right)^3}

\left(4^7\right)^3

=4^{21}

=\frac{4^{21}}{\left(5^2\right)^3}

\left(5^2\right)^3

5^6

=\frac{4^{21}}{5^6}

6 0
3 years ago
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