The answer i got was 49-9b^2
Answer:
x=0
Step-by-step explanation:
120521x=0
x=0/120521=0
<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
Answer:
E
Step-by-step explanation:
You just multiply 16 by 4.
(1)^3 /(3)^3
(1x1x1)/{3x3x3}
1/27 hope it helps :))