Answer: 2x³-10x²+12x or 2x(x²-5x+6)
Step-by-step explanation:
(p*q)(x) means p(x) and q(x) multiplied together.
(2x²-4x)(x-3)
2x³-6x²-4x²+12x
2x³-10x²+12x
You can also factor this by taking out a 2x.
2x(x²-5x+6)
Answer:
10kg//
Step-by-step explanation:
density=5g/cm
volume=2cm
mass=?
we know,
density=m/v
d×v=m
m=5×2
hence,10kg//
Answer:
probably 20 man think about it
Step-by-step explanation:
Answer:
The
3
mile cab ride includes a basic charge as well as the cost for the distance covered.
For a
6
mile trip, the cost is
$
4.80
which means that :
The cost of
3
miles is
$
4.80
−
$
3.00
=
$
1.80
Therefore the cost for
1
mile is
$
1.80
÷
3
=
$
0.60
The basic fee for hiring the cab is
$
3.00
−
$
1.80
=
$
1.20
So the total cost,
c
for a trip of
d
miles will be:
c
=
0.6
d
+
1.2
Check:
If
d
=
3
c
=
0.6
(
3
)
+
1.2
=
3
If
d
=
6
c
=
0.6
(
6
)
+
1.2
=
4.8
Step-by-step explanation:
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
