What percentage of the tickets sold were to Seniors?

Jessie has a piece of cardboard that is 8.5 inches by 11 inches. Sh makes a picture frame with the cardboard by cutting out a 4

vagabundo [1.1K]

First, we determine the area of the piece of cardboard by multiplying its dimensions.
area of cardboard = (8.5 inches) x (11 inches) = 93.5 in²
Then, we solve for the area of the cut out square,
area of the square = (4 inches) x (4 inches) = 16 in²
Then, we subtract the areas giving us the area of the frame which is equal to,
77.5 in²

7 0

3 years ago

Find the length of the missing side. 50 m 30 m The length of the missing side is m.

satela [25.4K]

Answer: The missing length is 40 m.

Step-by-step explanation:

30^2 + b^2 = 50^2

900 + b^2 = 2500

-900 -900

b^2 = 1600

b= 40

3 0

3 years ago

7x² + 6x - 1 Algebra 3|factoring

GaryK [48]

Answer:

(7 x - 1) (x + 1)

Step-by-step explanation:

Factor the following:

7 x^2 + 6 x - 1

Factor the quadratic 7 x^2 + 6 x - 1. The coefficient of x^2 is 7 and the constant term is -1. The product of 7 and -1 is -7. The factors of -7 which sum to 6 are -1 and 7. So 7 x^2 + 6 x - 1 = 7 x^2 + 7 x - x - 1 = (7 x - 1) + x (7 x - 1):

(7 x - 1) + x (7 x - 1)

Factor 7 x - 1 from (7 x - 1) + x (7 x - 1):

Answer: (7 x - 1) (x + 1)

5 0

3 years ago

A survey of 700 adults from a certain region asked, "What do you buy from your mobile device?" The results indicated that 59%

Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes $n_{1} = 400 and n_{2} = 300$

Proportion of mean $p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52$

Null hypothesis H0 : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

Alternative hypothesis H1:- p1 ≠ p2

a) The test statistic is

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }$

where $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

on calculation we get p = 0.56

now q =1-p = 1-0.56=0.44

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }\\ =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300} }$

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

conclusion:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) 95% confidence intervals

The confidence intervals are P± 1.96(√PQ/n)

we know that = $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of confidence intervals (0.523 ,0.596)

3 0

3 years ago

Explain how to simplify this complex fraction. 330pages/3/4hour.

meriva

Answer:
= 330/1 ÷ 3/4

= (330 × 4) / (3 × 1)

= 1320/3

= 440/1

= 440

Hope this helps!

7 0

3 years ago