1, 2, 4, 8, 16 ...
a = 1
d = 8/4 = 2
Sn = n/2(2a + (n-1)d) = 30(2 + (29×2)) = 30(60) = 1800
Ans = $1,800 ...//
Answer:
one solution
Step-by-step explanation:
Answer:
I think it's 7
Step-by-step explanation:
I'm guessing I think
Answer: 25, 31 and 37
Step-by-step explanation:
(2n-1)= 19, 21, 23, 25, 27, 29, 31, 33, 35, 37
(3n+1)= 19, 22, 25, 28, 31, 34, 37,
Answer:
A. 0.5
B. 0.32
C. 0.75
Step-by-step explanation:
There are
- 28 students in the Spanish class,
- 26 in the French class,
- 16 in the German class,
- 12 students that are in both Spanish and French,
- 4 that are in both Spanish and German,
- 6 that are in both French and German,
- 2 students taking all 3 classes.
So,
- 2 students taking all 3 classes,
- 6 - 2 = 4 students are in French and German, bu are not in Spanish,
- 4 - 2 = 2 students are in Spanish and German, but are not in French,
- 12 - 2 = 10 students are in Spanish and French but are not in German,
- 16 - 2 - 4 - 2 = 8 students are only in German,
- 26 - 2 - 4 - 10 = 10 students are only in French,
- 28 - 2 - 2 - 10 = 14 students are only in Spanish.
In total, there are
2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.
The classes are open to any of the 100 students in the school, so
100 - 50 = 50 students are not in any of the languages classes.
A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is

B. If a student is chosen randomly, the probability that he or she is taking exactly one language class is

C. If 2 students are chosen randomly, the probability that both are not taking any language classes is

So, the probability that at least 1 is taking a language class is
