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eimsori [14]
3 years ago
12

Please show your work

Mathematics
1 answer:
White raven [17]3 years ago
3 0

Let a,b & c be the number of cookies Adrian, Bobby and Calvin baked respectively.

(a+b+c)/3 =138

(a+b)/2 =136

a+b=272

a=272-b

(b+c)/2 =125

b+c=250

c=250-b

Sub a=272-b and c=250-b into (a+b+c)/3 =138,

(a+b+c)/3 =138

[(272-b)+b+(250-b)]/3 = 138

272-b+b+250-b = 414

-b = -108

b=108

From the above,

a=272-b

=272-108

a=164

c=250-b

=250-108

c=142

∵ a=164

b=108

c=142

∴ Adrian baked 164 cookies.

Bobby baked 108 cookies.

Calvin baked 142 cookies.

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An elementary school is offering 3 language classes: one in Spanish, one in French,and one in German. The classes are open to an
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A. 0.5

B. 0.32

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Step-by-step explanation:

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  • 26 in the French class,
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  • 4 that are in both Spanish and German,
  • 6 that are in both French and German,
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So,

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  • 4 - 2 = 2 students are in Spanish and German, but are not in French,
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\dfrac{50}{100} =0.5

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C. If 2 students are chosen randomly,  the probability that both are not taking any language classes is

0.5\cdot 0.5=0.25

So,  the probability that at least 1 is taking a language class is

1-0.25=0.75

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