Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:

We substitute x=161.4 ,
, and
to get:

From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Answer:
68%
Step-by-step explanation:
= 68%
I hope this helps!
Answer:
0, π
Step-by-step explanation:
cos x sin x = sin x
cos x sin x - sin x = 0
sin x (cos x - 1) = 0
sin x = 0, x = 0, π
cos x - 1 = 0
cos x = 1, x = 0
So answers: 0, π
0.06 times 96 equals 5.76
<span><span>θi</span>=<span>sin<span>−1</span></span>(μsin<span>θr</span>)
=<span>sin<span>−1</span></span>(1.33×sin46.5)
=74.7degrees</span>