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3 years ago

15 POINTS WILL MARK BRAINLIEST!!!!! Choose the group responsible for the Declaration of Independence.

Mathematics

1 answer:

Bess [88]3 years ago

6 0

Answer: second Congress

Step-by-step explanation:

Short and sweet

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Reduce <br>0.1 x squared - 8.1 x + 8 = 0 to<br>2x squared - x + 80 = 0<br><br>

Yuliya22 [10]

Answer:

x = 8

x = -10

Step-by-step explanation:

7 0

2 years ago

I need an answer NOT A LINK! ASAP

katen-ka-za [31]

Answer:

D. No, because group A is already the control group.

7 0

2 years ago

F(n) = n² – 3 g(n) = 4n - 1 Find f[g(1)]

SVETLANKA909090 [29]

Answer:

f[g(1)]=6.

Explanation:

Given f(n) and g(n) defined below:

$\begin{gathered} f\mleft(n\mright)=n^2-3 \\ g\mleft(n\mright)=4n-1 \end{gathered}$

First, we evaluate g(1):

$\begin{gathered} g\mleft(1\mright)=4(1)-1 \\ =4-1 \\ g(1)=3 \end{gathered}$

Therefore:

$\begin{gathered} f\mleft(g(1)\mright)=f\mleft(3\mright) \\ f\mleft(3\mright)=3^2-3 \\ =9-3 \\ =6 \end{gathered}$

Therefore, f[g(1)]=6.

8 0

1 year ago

The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge

Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

$5x+4y+5z=-1$

$x+y+2z=1$

$2x+y-z=-3$

Firs we find determinant of system of equations

Let a matrix A= $\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right]$ and B= $\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]$

$\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}$

$\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0$

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply $R_1\rightarrow R_1-4R_2$ and $R_3\rightarrow R_3-2R_2$

$\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]$

Apply $R_2\rightarrow R_2-R_1$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]$

Apply $R_3\rightarrow R_3+R_2$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]$

Apply $R_3\rightarrow- \frac{1}{2}$ and $R_2\rightarrow R_2-R_3$

$\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Apply $R_1\rightarrow R_1-R_3$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0

3 years ago

WILL MARK BRAINLIEST HELP ASAP ASAP

Kamila [148]

Answer:

C. AAS

Step-by-step explanation:

they share 2 angles(A) you can tell by the markings and they share that one side

by this point you have 2 options left

ASA

AAS

the angles are right next to each other so it's AAS

7 0

3 years ago