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ExtremeBDS [4]
3 years ago
15

Tracie ran a total of 5 3/4 miles on Saturday and Sunday. She ran 1 5/8 miles on Saturday . How many miles did Tracie run on Sun

day ?
Mathematics
1 answer:
mylen [45]3 years ago
8 0

Tracie ran \frac{33}{8} miles or 4\frac{1}{8} miles on sunday

<u><em>Solution:</em></u>

Given that Tracie ran a total of 5\frac{3}{4} miles on Saturday and Sunday

She ran 1\frac{5}{8} miles on Saturday

To find: Number of miles ran on Sunday

From given question,

Total miles ran on Saturday and Sunday = 5\frac{3}{4} miles

\rightarrow 5\frac{3}{4} = \frac{4 \times 5+3}{4} = \frac{23}{4} \text{ miles}

Miles ran on Saturday = 1\frac{5}{8} miles

\rightarrow 1\frac{5}{8} = \frac{8 \times 1+5}{8}=\frac{13}{8} \text{ miles }

Number of miles ran on sunday = Total miles ran on Saturday and Sunday - Miles ran on Saturday

Number of miles ran on sunday = \frac{23}{4} -\frac{13}{8}

\rightarrow \frac{23}{4} -\frac{13}{8}\\\\\rightarrow \frac{23 \times 2}{4 \times 2}-\frac{13}{8}\\\\\rightarrow \frac{46}{8} - \frac{13}{8}\\\\\rightarrow \frac{46-13}{8} = \frac{33}{8}

\rightarrow \frac{33}{8} = 4\frac{1}{8}

Thus Tracie ran \frac{33}{8} miles or 4\frac{1}{8} miles on sunday

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Andre45 [30]

Answer:

1. (1,1)

2.(2,-6)

3.Not sure.

4.No solution

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Step-by-step explanation:

Hope that helps bud!:)

5 0
2 years ago
Labrador Retriever weighs 48 kg after a diet and exercise program the dog weighs 43 kilograms to determine if this shows a perce
ExtremeBDS [4]

Answer:

percentage change in weight ≈ 10%

Step-by-step explanation:

The dog weighed 48 kg after a diet and after an exercise program the dog had a weight of 43 kg. This means the dog loss weight since the dog weight decreased from an initial value of 48 kg to 43 kg. The decrease in weight can be calculate as

decrease in weight = original weight - new weight

original weight  = 48 kg

new weight = 43 kg

decrease in weight = 48 - 43 = 5 kg

Since the weight decrease their will be a percentage decrease in weight.

% decrease = decrease in weight/original weight × 100

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% decrease = 500/48

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5 0
3 years ago
In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p
skelet666 [1.2K]

Answer:

\mathbf{P(X=5) =0.0888}    

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

\mathtt{P(X=x) =(^{n}_{x} )   \  \pi^x \  (1-\pi)^{n-x}}

\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} )   \  \pi^x \  (1-\pi)^{n-x}}

where;

n = 8 and π = 0.36

For x = 5

The probability \mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} )   \  0.36^5 \  (1-0.36)^{8-5}}

\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} )   \  0.36^5 \  (0.64)^{3}}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =({8 \times 7 } )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =0.0887645}

\mathbf{P(X=5) =0.0888}     to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5)\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})

{P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times  (0.36)^0  \times  (1-0.36)^8  \ )  +  \dfrac{8!}{1!(7!)} \times  (0.36)^1  \times  (1-0.36)^7  \ +\dfrac{8!}{2!(6!)} \times  (0.36)^2  \times  (1-0.36)^6  \ +  \dfrac{8!}{3!(5!)} \times  (0.36)^3  \times  (1-0.36)^5 +  \dfrac{8!}{4!(4!)} \times  (0.36)^4  \times  (1-0.36)^4  \  +  \dfrac{8!}{5!(3!)} \times  (0.36)^5  \times  (1-0.36)^3  \ )

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1  - P( x  ≤ 5 )

P ( x ≥ 6) = 1  - 0.9707

P ( x ≥ 6) = 0.0293

4 0
3 years ago
Can someone help me with this and show their work and how they found the answer?
Semenov [28]

Answer:

2kg

Step-by-step explanation:

Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be

H = 2/3 * R

= 2R/3

Given that the 3 bricks weigh 5kg in total then,

2R/3 + R = 5

Multiply through the equation by 3

2R + 3R = 15

5R = 15

Divide both sides by 5

R = 15/5

= 3

The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs

= 2 * 3/3

= 2kg

4 0
3 years ago
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