Answer:
41.7feet
Step-by-step explanation:
From the question we are given the following
angle of depression = 50°
Distance of the pole from the base of the feet = 35feet (Adjacent)
Required
height of the school (opposite)
Using the SOH CAH TOA identity
Tan theta = opp/adj
Tan 50 = H/35
H = 35tan 50
H = 35(1.1918)
H = 41.7feet
Hence the height of the school is 41.7feet
See the denomenators
x^2 and 5x
factor each
x^2=x*x
5x=5*x
lcd=5*x*x or 5x^2
the factions would be 35/5x^2 and 7x/5x^2
<span>P=1/2 x(y+z)
</span><span>P=1/2 (6)[9 + 7]
P = 3(16)
P = 48
hope it helps</span>
That you owe someone some money
