Hello,
The answer is B
Hope this helped :)
<h2>
Answer:</h2>
A. It is a many-to-one function.
<h2>
Step-by-step explanation:</h2>
Hello! It will be a pleasure to help to figure out what's the correct answer to this problem. First of all, we have the following function:

When plotting this function, we get the red graph of the function shown below. So let's solve this as follows:
<h3>A. It is a many-to-one function.</h3>
True
A function is said to be many-to-one there are values of the dependent variable (y-values) that corresponds to more than one value of the independent variable (x-values). To test this, we need to use the Horizontal Line Test. So let's take the horizontal line
, and you can see from the first figure below that
is mapped onto
. so this is a many-to-one function.
<h3>B. It is a one-to-one function.</h3><h3>False</h3>
Since this is a many-to-one function, it can't be a one-to-one function.
<h3>C. It is not a function.</h3>
False
Indeed, this is a function
<h3>D. It fails the vertical line test.</h3>
False
It passes the vertical line test because any vertical line can intersect the graph of the function at most once. An example of this is shown in the second figure below.
We have to determine the equation of the line passing through the point (2,-5) and parallel to the line 
When two lines are parallel, then the slopes of the two lines are equal.
Equation of line with point
and slope 'm' is given by:

Since, we have to determine the equation of a line with point (2,-5).
So, the equation of the line is : 

Since, the line is parallel to the line 
So, 


So, slope of the line 'm' is
.
Therefore, the equation of the line is:




Therefore,
is the required equation of the line.
The event that either M1 or M2 fails has probability

by the addition rule. Failure events are independent, so

so that

Denote this probability by
. Then
follows a geometric distribution with this parameter
and has density

The expectation is
.
The effect on the photos perimeter and area would be that the resulting photo would be larger than intended.