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love history [14]
3 years ago
9

How to shade a grid for 1.96

Mathematics
1 answer:
almond37 [142]3 years ago
8 0
First, u shade in one whole grid which will equal 1 whole. Then, make a another grid and shade in 9 rods and 6 units
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Valeria operates an orange juice stand. On Monday, she used 4 1/2
torisob [31]

Answer:

0.37

Step-by-step explanation:

5 0
3 years ago
For questions 9 and 11, solve for the remaining angles.
maw [93]

Answer:

‹A = 141°

‹B = 28°

‹C = 11°

*These angles are rounded to the nearest whole*

Step-by-step explanation:

Because you are only given sides you can find an individual angle measures with the inverse law of cosines.

Remember the side opposite of the angle corresponds to that angle.

a² = b² + c² - 2bc cos(A) →

A = cos⁻¹ (a² - b² - c² / -2bc)

b² = a² + c² - 2ac cos(B) →

B = cos⁻¹ (b² - a² - c² / -2ac)

c² = a² + b² - 2ab cos(C) →

C = cos⁻¹ (c² - a² - b² / -2ab)

4 0
2 years ago
SEE ATTACHED
fenix001 [56]
To me personally, the first bit f(g(x)) is easy and the domain is tricky. Let's try explain this.

A function takes an input number and returns an output number depending on the function. Look at f(x) = x+3, if we let the input number be 2 then we say that f(2) = 5. We could do f(π) to give us π+3 or even f(x²) to give us x² +3. The trick is to substitute the input into the function equation.

You have been asked to find f(g(x)). You know f(x) = \frac{1+x}{1-x}. Putting numbers in at this point would be easy (try work out f(2), you'll do it really quick) but you have to put in g(x).

f(g(x)) = \frac{1+g(x)}{1-g(x)}
we also know that g(x) = \frac{x}{1-x} so we can say that
f(g(x)) = \frac{1+ \frac{x}{1-x} }{1- \frac{x}{1-x} } and that is f(g(x)) but the question requires that we simplify it so
\frac{1+ \frac{x}{1-x} }{1- \frac{x}{1-x} }  =  \frac{ \frac{1-x}{1-x} +  \frac{x}{1-x} }{ \frac{1-x}{1-x} - \frac{x}{1-x} } =  \frac{ \frac{1}{1-x} }{ \frac{1-2x}{1-x} } =  \frac{1}{1-2x}

f(g(x)) = \frac{1}{1-2x}

Now for the tricky bit (for me, at least). The domain is the full set of values that you can 'put in to' the function and still get a real value out. So how do we work out what numbers 'break' the function? I like to use the fact that DIVIDING BY ZERO IS IMPOSSIBLE. What value of x can we put into the function to make it so the function is being divided by 0? i.e. 1-2x = 0 solve that and you have a value of x that isn't part of the domain.

This means the domain is all real numbers EXCEPT the solution to that equation. (Because if we put that value into f(g(x)) it's impossible to get a value out.)

[I know this was a lot to read, if you have any questions or don't get anything feel free to message me or leave a comment.]

5 0
3 years ago
A store sells grass seed in small bags and large bags. The small bags have 7 pounds of seed for $27.93 and the large bags have 2
Arada [10]

Answer:

The 20 pound bag is a better by for only $66.98

Step-by-step explanation:

The large bag is better because the small bag is $27.93 for 7 pounds 7x3=21,so 3x27.93=83.79 is $16.81 more than the cost for the large bag

hope this makes sense;)

5 0
3 years ago
Round the fraction 7 4/5 to the nearest whole number
Over [174]
Im not sure if you are saying 74/5 or 7 and 4 fifths but in the case you'r saying 74/5 you would first round to see the highest number that 5 can go to without being a decimal. Which would be 70 so you would count how many times 5 can go into 70, which would be 14, so the left over is 4/5 so you would check to see if it can be simplified which it can't so the final answer is 14 and 4/5
3 0
3 years ago
Read 2 more answers
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