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Karo-lina-s [1.5K]
3 years ago
9

PLEASE HELPPPPP.

Mathematics
1 answer:
olasank [31]3 years ago
3 0
1. You'd divide 98,000,000 by 750,000 and get about 131 trees per acre ("population" density).

2. 131 trees/acre x 750,000 = 98,250,000trees.
         Then 292,000,000 divided by98,250,000, which is 2.9 Round up to 3 boxes/tree.

Hope I helped. Hope this makes sense.

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What is 12/25 divided by 4
UNO [17]
In order to find the answer to this, you must first turn 4 into a fraction (4/1)

12/25 divided by 4/1 is the same as 12/25 multiplied by 1/4, because when dividing fractions, you must use the reciprocal of the divisor and multiply.

12/25 x 1/4 = 12/100 = 6/50 = 3/25

Your answer should be 3/25<span />
5 0
3 years ago
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The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature
Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}

Where

(t) = \ time

T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)

T_{s} = Surrounding \ temperature

T_{0} = Initial \ temperature \ of \ the \ body

k = constant

From the question,

T_{0} = 86 ^{o}C

T_{s} = -20 ^{o}C

∴ T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C

T_{0} - T_{s} = 106^{o} C

Therefore, the equation T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt} becomes

T_{(t)}=-20+106 e^{kt}

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time t = 1 \ hour, T_{(t)} = 58^{o}C

Then, we can write that

T_{(1)}=58 = -20+106 e^{k(1)}

Then, we get

58 = -20+106 e^{k(1)}

Now, solve for k

First collect like terms

58 +20 = 106 e^{k}

78 =106 e^{k}

Then,

e^{k} = \frac{78}{106}

e^{k} = 0.735849

Now, take the natural log of both sides

ln(e^{k}) =ln( 0.735849)

k = -0.30673

This is the value of the constant k

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at t = 2 \ hours

From

T_{(t)}=-20+106 e^{kt}

Then

T_{(2)}=-20+106 e^{(-0.30673 \times 2)}

T_{(2)}=-20+106 e^{-0.61346}

T_{(2)}=-20+106\times 0.5414741237

T_{(2)}=-20+57.396257

T_{(2)}=37.396257 \ ^{o}C

T_{(2)} \approxeq  37.40 \ ^{o}C

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0
2 years ago
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The table displays the amount of time, in minutes, Jordan rode his bike for five days. How many total hours did Jordan ride his
Zinaida [17]

Answer:98.9276

Step-by-step explanation:

The table displays the amount of time, in minutes, Jordan rode his bike for five days.  How many total hours did Jordan ride his bike in the five days?  ​​DayTime (minutes)​​11  ​4545  ​22  ​109109  33 ​5151 ​​44  ​121121  ​55  ​3838  ​Jordan rode his bike  total hours in the five days.

8 0
2 years ago
What is the mean of the set of numbers?
Llana [10]
The mean of your question would be -2.5
3 0
2 years ago
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How do I Solve this problem?
nlexa [21]
U would factor by grouping and get x^2(x-2) + 3(x-2) and then get (x^2 +3) (x-2)
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3 years ago
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