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Sergeeva-Olga [200]
3 years ago
13

K/6 = 15/18 Solve the proportion

Mathematics
2 answers:
Ilya [14]3 years ago
8 0

Answer:

k = 5

Step-by-step explanation:

<u>Step 1:  Cross multiply</u>

k/6 = 15/18

k(18) = 6(15)

<em>18k = 90</em>

<u>Step 2:  Divide both sides by 18</u>

18k / 18 = 90 / 18

<em>k = 5</em>

Answer:  k = 5

<u>Another way to do it is to multiply both sides by 6</u>

k/6 * 6 = 15/18 * 6

k = 90 / 18

<em>k = 5</em>

muminat3 years ago
7 0

Answer: 5

Step-by-step explanation: To solve for <em>k</em> in the given proportion, we use the means-extremes property. The product of the extremes, (k)(18), equals the product of the means, (6)(15).

So we have (k)(18) or 18k = (6)(15) or 90.

Now we have the equation 18k = 90.

Dividing both sides by 18, <em>k = 5</em>.

It's a good idea to check the answer in these types of problems so if we plug a 5 back in for <em>k</em> in the original proportion, we have \frac{(5)}{6}= \frac{15}{18} which is a true statement since 15/18 reduces to 5/6.

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A particular​ country's exports of goods are increasing exponentially. The value of the​ exports, t years after 2008​, can be ap
Alex_Xolod [135]

Answer:

a) For 2008 we have that t = 2008-2008 = 0 and we have:

V(0)= 1.4e^{0.039*0}= 1.4

For 2022 we have that t = 2022-2008=14 and if we replace we got:

V(12) = 1.4 e^{0.039*14}=2.417

b) 2.8 = 1.4 e^{0.039 t}

We can divide both sides by 1.4 and we got:

2 = e^{0.039 t}

Now natural log on both sides:

ln (2) = 0.039 t

t = \frac{ln(2)}{0.039}= 17.77 years

Step-by-step explanation:

For this case we have the following model given:

V(t) = 1.4 e^{0.039 t}

Where V represent the exports of goods and the the number of years after 2008.

Part a

Estimate the value of the country's exports in 2008 and 2022

For 2008 we have that t = 2008-2008 = 0 and we have:

V(0)= 1.4e^{0.039*0}= 1.4

For 2022 we have that t = 2022-2008=14 and if we replace we got:

V(12) = 1.4 e^{0.039*14}=2.417

Part b

What is the doubling time for the value of the country's exports.

For this case we can set up the following condition:

2.8 = 1.4 e^{0.039 t}

We can divide both sides by 1.4 and we got:

2 = e^{0.039 t}

Now natural log on both sides:

ln (2) = 0.039 t

t = \frac{ln(2)}{0.039}= 17.77 years

3 0
3 years ago
What is the debate among scientists on how new species form?
vekshin1

Answer:

read explanation

Step-by-step explanation:

Like most areas of Evolutionary Biology, research related to the formation of new species - 'speciation ' - is rich in historical and current debate.

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Simplify the expression so there is only one positive power for each base. (5^-2 x 4^-4)^-2
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Answer:

Step-by-step explanation:

(5^{-2} × 4^{-4} )^{-2}

=(5^{-2})^{-2} x (4^{-4})^{-2}                            ∴(a.b)^{n} =a^{n} .b^{n}

=5^{-2.-2} x 4^{-4 . -2}                              ∴(a^{n} )^{m} = a^{nm} // here m is an exponent of a^{n}.

=5^{4} x 4^{8}

4 0
3 years ago
NO LINKS OR ASSESSMENT!!<br><br>Write a rule to describe each transformation #9 &amp; #11​
ValentinkaMS [17]

Answer:

Step-by-step explanation:

Remark

I really don't know what to write to these questions. I can never tell what the problem is. Perhaps it is right at the very beginning. You have to recognize what is taking place. In problem 9, the easiest point to follow is H going to H'. Do you see what is happening? H is sitting on the x axis and then something happens to it and behold, it is now sitting on the y axis. So it has rotated 90 degrees but which way?

Take your finger or a pencil and put it on H. Then make a circular motion to get to H'. You are going clockwise. (keep going in that direction till you wind up where you started. You are going in the direction of one of those old fashioned clocks. Now the trick in a rotation is if you can figure out what one point is doing, you know what all points are doing on the given figure.

So the translation is 90 degrees clockwise. That means the following rule must be operating

(x,y) ===> (y, - x)

H(-3,0) ===> H'(0, - - 3) = H'(0,3)

I(-2,1) =====>I'(1, - - 2) = H'(1,2)

J(0,1) =====>J'(1,0)

G(-3,-3)====>G'(-3, --3) = G'(-3,3)

11

At first you may think that this is a translation of some kind. I thought so at first. D and D' certainly look that way and C and C' also look that way. But B and E are not well behaved. You are looking at a 180 degree rotation

The rule you need here is (x,y) becomes (-x , - y)

I'll leave C and D to you and do one of the B and E

E(3,5)=E'(-3 , - 5)

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3 years ago
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7 0
3 years ago
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