K/6 = 15/18 Solve the proportion
2 answers:
Answer: 5
Step-by-step explanation: To solve for <em>k</em> in the given proportion, we use the means-extremes property. The product of the extremes, (k)(18), equals the product of the means, (6)(15).
So we have (k)(18) or 18k = (6)(15) or 90.
Now we have the equation 18k = 90.
Dividing both sides by 18, <em>k = 5</em>.
It's a good idea to check the answer in these types of problems so if we plug a 5 back in for <em>k</em> in the original proportion, we have which is a true statement since 15/18 reduces to 5/6.
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Answer:
A.) x-y=2 and x+2y=-2
Step-by-step explanation:
For option A, we have:
x-y=2
x+2y=-2
Subtract the first equation from the second, to get:
2y--y=-2-2
This implies that:
2y+y=-2-2
Simplify to get:
3y=-4
Divide both sides by 3 to get:
We substitute y=-1.3 into the first equation to get:
x--1.3=2
x+1.3=2
x=2-1.3
x=0.7
The solution is (0.7,-1.3), which is approximately (0.7, -1.4)
By inspection, all the other factors have solutions not close to (0.7, -1.4)
Answer:
Average size of the lots = ⅓ acre
Step-by-step explanation:
The question incomplete without specifying what we are to determine.
Question:A builder is buying property where she can build new houses. The line plot shows the sizes for each house. 1/6 has 6 X's 1/3 has 3 X's and 1/2 has 6 X's. Organize the information in a line plot. What is the average size of the lots? _________ acre
Help anyone?
Solution:
We are asked to organize the information in a line plot. See attachment for the line plot.
Given: 1/6 has 6 X's 1/3 has 3 X's and 1/2 has 6 X'sIn no particular order, the sizes of the lots are:1/6, 1/6, 1/6, 1/6, 1/6, 1/6, 1/3, 1/3, 1/3, 1/2, 1/2, 1/2, 1/2, 1/2 and 1/2 acre.
Let's count the number of lot for each size given.
For 1/6: there are 6 X's on the line plot of 1/6 number of lot for 1/6
= the lot × number of times it occurs
= (1/6) × 6 = 6/6 = 1 acre
For 1/3: there are 3 X's on the line plot of 1/3 number of lot for 1/3 = the lot × number of times it occurs
= (1/3) × 3 = 3/3 = 1 acre
For 1/2: there are 6 X's on the line plot of 1/2 number of lot for 1/2
= the lot × number of times it occurs
= (1/2) × 6 = 6/2= 3 acres
To find average size of the lots, we would sum all lot for each given size then divide by the total number of lots given.Sum of all lot for each given size = 1+1+3
Sum of all lot for each given size = 5
The total number of lots given = 15
Average size of the lots = 5/15 = 1/3
Average size of the lots = ⅓ acre
