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Vladimir79 [104]
3 years ago
5

The circumference of a hula hoop is 86 pi cm. What is the radius of the hula hoop?

Mathematics
2 answers:
Degger [83]3 years ago
6 0

Answer:

86/ 2x3.14

86/6.28

answer: 13.69426 (round it)

Step-by-step explanation:

Amanda [17]3 years ago
3 0

Answer:

Radius is 43/π

Step-by-step explanation:

<u>Circumference of a circle:  C = 2πr</u>

<u />

<u>Step 1:  Solve for r</u>

86 / 2π = 2πr / 2π

<em>43/π = r</em>

<em />

Answer:  Radius is 43/π

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Determine whether the following probability experiment represents a binomial experiment and explain the reason for your answer.S
kozerog [31]

Answer:

B., C. and D.

Step-by-step explanation:

Seven cards are selected from a standard​ 52-card deck without replacement. The number of diamonds selected is recorded. Does the probability experiment represent a binomial​ experiment?

<em><u>The criteria for a Binomial experiment are the following.</u></em>

<em><u /></em>

<em>1. Fixed number of trials. </em>(Not met)

The text doesn't specify the sample size (it says that seven cards are selected but doesn't specify how many times will seven cards be drawn), this number must be established before starting the experiment.

<em>2. There are only two possible outcomes for each trial.</em> (Not met)

"Draws seven cards and records the number of diamonds" so the outcome of the trial can be

"No diamonds"

"1 diamond card"

"2 diamond cards"

"3 diamond cards"

...

"7 diamond cards"

Simply speaking, it has two outcomes if you can phrase it as a yes or no question. That is not the case in this experiment.

<em>3. Each trial is an independent event.</em> (Not met)

<em>4. The probability of success in the same from one trial to another.</em> (Not met)

Two events are independent if the occurrence of one doesn't affect the probability of occurrence of the next one.

Since the cards are selected without replacement, at each repetition of the trial the probability of the next trial is modified. Therefore, the trials are dependant and the probability of success is modified after each trial.

None of the criteria for a Binomial experiment are met, this is not a Binomial experiment.

I hope you have a SUPER day!

3 0
4 years ago
Amanda brought a 6-cup of bag of shredded cheese for $6.89. She used 2.25 cups to make lasagna and 1.25 cups to make pizza. How
valina [46]
1 piece of cheese is left because 2.25-1.25 equals 1
5 0
3 years ago
An insurance company study shows that 9% of U. S. adults have diabetes. Suppose 8 US adults are selected at random. LetX be the
Bogdan [553]

Using the binomial distribution, it is found that:

  • The mean of X is of 0.72.
  • The standard deviation of X is of 0.81.

<h3>What is the binomial probability distribution?</h3>

It is the probability of exactly <u>x successes on n repeated trials, with p probability </u>of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

For this problem, the parameters are given as follows:

n = 8, p = 0.09.

Hence the mean and the standard deviation are, respectively:

  • E(X) = np = 8 x 0.09 = 0.72.
  • \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{8 \times 0.09 \times 0.91} = 0.81

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

3 0
2 years ago
Help meeeee pweaassee!!
mariarad [96]

Answer:

7. divide both sides by 18.

8. subtract 4 from both sides.

9. add 3 on both sides.

10. multiply by 6 on both sides

Hope that helps! :3

Step-by-step explanation:

5 0
3 years ago
Which shows like terms from the expression? 9 + 5 + 7x2 + 3 x2y + 2x2 3 x2y and 2x2 7x2, 3 x2y, and 2x2 9 and 5 2, 3, 5, and 9
snow_lady [41]

Answer:

9 and 5.

Step-by-step explanation:

So we have the expression:

9+5+7x^2+3x^2y+2x^2

In order to combine like terms, the variables must be <em>exactly</em> the same: not one less, not one more.

3x²y and 2x² <em>cannot</em> be combined because the first value has a y.

7x², 3x²y, and 2x² also <em>cannot </em>be combined because the second value has a y.

9 and 5 is the only one that can be combined because they are just integers. They can be added to be 14.

2, 3, 5, and 9 <em>cannot</em> be combined because the 2 and the 3 are tied to the variables as coefficients. They are not constants.

5 0
3 years ago
Read 2 more answers
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