V=(1/3)πr²h
∴ dV/dt
=(π/3)[r²(dh/dt)+h2r(dr/dt)]
=(π/3)[(30)²(-2)+40(2)(30)(2)]
=(π/3)[-1800+4800]
=1600π in³/sec
Answer: 1600π in³/sec
\oint is what you're looking for
Answer:
x = -2
Step-by-step explanation:
Divide both sides by 3
3 (2x + 5)/3 = 3/3
Simplify
2x + 5 = 1
Subtract 5 from both sides
2x + 5 - 5 = 1 - 5
Simplify
2x = -4
Divide both sides by 2
2x/2 = -4/2
Simplify: 2x/2
Divide the numbers: 2/2 = 1
= x
Simplify: -4/2
Apply the fraction rule: -1/b = -a/b
= - 4/2
Divide the numbers: 4/2 = 2
= -2
x = -2
6 x (-3) = -18
6 + (-3) = 3
The numbers are 6 and -3
