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Lina20 [59]
3 years ago
8

Find the sum of the interior angles of a regular 32-gon. Then find the measure of each angle.

Mathematics
1 answer:
Law Incorporation [45]3 years ago
5 0
Answer is b Fosho Fosho
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dolphi86 [110]

4/6 divided by 2/6 is 2.

you multiply the 4/6 by 6/2 to get 24/12. You then simplify it and get 2 as your answer.

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What is the area of the trapezoid shown? (1) angle a = 120 degrees (2) the perimeter of trapezoid abcd = 36?
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Not enough information to solve this
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Ms.acton spent 205.60 at target. If the sales tax is 6% what was her final bill
guajiro [1.7K]

Answer: just put c

Step-by-step explanation:

C is always correct

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If Susie is 14, what was her age x years ago?<br><br> A.) x - 14<br> B.) 14 - x<br> C.) 14x
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Susie's age from x years ago would be the difference of her current age and the numbers of years that passed which is x. The expression that best represent her age x years ago is 14 - x. Thus, the answer is letter "B. 14 - x". 
4 0
3 years ago
Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?
vichka [17]

Answer:

The expression -1+14i represents  the number 2i^4-5i^3+3i^2+\sqrt{-81} rewritten in a+bi form.

Step-by-step explanation:

The value of i is i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4} in term of i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}

Substituting the value,

i^{4}=\left(-1\right)\times \left(-1\right)

Product of two negative numbers is always positive.

\therefore i^{4}=1

Now i^{3} in term of i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i

Substituting the value,

i^{3}=\left(-1\right)\times i

Product of one negative  and one positive numbers is always negative.

\therefore i^{3}=-i

Now \sqrt{-81} can be written as follows,

\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}

Applying radical multiplication rule,

\sqrt{ab}={\sqrt{a}}\sqrt{b}

\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}

Now, \sqrt{\left(81\right)=9 and \sqrt{-1}}=i

\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i

Now substituting the above values in given expression,

2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i

Simplifying,

2+5i-3+9i

Collecting similar terms,

2-3+5i+9i

Combining similar terms,

-1+14i

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0
3 years ago
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