4 years ago

Identify a pair of exterior angles. 1 and 5 8 and 4 2 and 5 1 and 8

Mathematics

1 answer:

Alenkasestr [34]4 years ago

7 0

Answer:

1 and 8

Step-by-step explanation:

Extierior think of it as interior is the inside they both start with in and then extierior is the outside

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The width of a rectangle is two cm less than 8 times the length. The perimeter is 88 cm. What is the width and length of the rec

kati45 [8]

Let's the length to be x,

then the width is 8x - 2.

Perimeter of a rectangle = 2*Width + 2*Length

Perimeter of the rectangle = 2(8x-2) + 2x = 16x - 4 + 2x = 18x - 4

Ar the same time, Perimeter of the rectangle = 88.

So, we can write

18x - 4 = 88

18x = 84

9x=42

x= 42/9 cm (length) or ≈ 4.67 cm (length)

8x - 2 = 8*42/9 - 2 ≈ 35.33 cm (width)

6 0

4 years ago

Verify the identity. Show your work. (1 + tan^2u)(1 - sin^2u) = 1

yuradex [85]

$\bf \textit{Pythagorean Identities}
\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\ 1+tan^2(\theta)=sec^2(\theta)\\\\
-------------------------------\\\\\
[1+tan^2(u)][1-sin^2(u)]=1
\\\\\\\
[sec^2(u)][cos^2(u)]\implies \cfrac{1}{cos^2(u)}\cdot cos^2(u)\implies \cfrac{cos^2(u)}{cos^2(u)}\implies 1$