Question

The second side of a triangular deck is 3 feet longer than the shortest side and a third side that is 3 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 76
feet, what are the lengths of the three sides?

Answer 1

Considering the perimeter of the triangle, it is found that the lengths of the sides are given by:

19 feet, 22 feet, 35 feet.

What is the perimeter of a triangle?

The perimeter of a triangle is given by the sum of the lengths of it's sides.

For this problem, we consider the sides as:

x, y and z.

The perimeter is of 76 feet, hence:

x + y + z = 76.

The second side of a triangular deck is 3 feet longer than the shortest side, hence:

y = x + 3.

A third side that is 3 feet shorter than twice the length of the shortest side.

z = 2x - 3.

Applying everything at the perimeter equation, we have that:

x + y + z = 76.

x + x + 3 + 2x - 3 = 76.

4x = 76.

x = 76/4

x = 19.

Then the other variables are:

• y = x + 3 = 22.

• z = 2x - 3 = 2(19) - 3 = 35.

The lengths are:

19 feet, 22 feet, 35 feet.

More can be learned about the perimeter of a triangle at brainly.com/question/24382052

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