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Oliga [24]
4 years ago
13

Calculate the area of the circle round your answer to the nearest hundreds ​

Mathematics
1 answer:
Sergeu [11.5K]4 years ago
6 0
This is confusing? What answer?
You might be interested in
Write 4 3/5<br> as an improper fraction.
Andrews [41]

Answer:

\frac{23}{5}

Step-by-step explanation:

4 3/5

\frac{4 \times 5 + 3}{5}

\frac{20 + 3}{5}

= 23/5

8 0
3 years ago
Read 2 more answers
Use the Pythagorean theorem to prove whether or not each set of numbers represent the side lengths of a right triangle.
pav-90 [236]

Answer:

A is not a right triangle

B is a right triangle

Step-by-step explanation:

A.

6^2 = 36
12^2 = 144.

36 + 144 = 180

15^2 = 225

180 ≠ 225, so it is not a right triangle

----------------------------------------------------------------------------

B.

5^2 = 25

12^2 = 144

25 + 144 = 169

13^2 = 169

169 = 169, so it is a right triangle

4 0
3 years ago
Genie is a dental hygienist. She has 15 boxes of mint dental floss that have 16.4
HACTEHA [7]

Answer:

789.4 tards of dental floss

Step-by-step explanation:

multiply 11 by 49.4 which gives you 543.4 then multiply 15 by 16.4 then add up your answers and then you have your correct answer.

5 0
3 years ago
Read 2 more answers
What is the value of x?
KatRina [158]

Answer:

X = 98°

Step-by-step explanation:

53° + 45° + FGH = 180° ( Interior angle property)

FGH = 180° - 98 °

FGH = 82°

Now,

By x would be solved through linear pair.

x° + 82° = 180° ( linear pair)

x° = 180° - 82°

x = 98°

hope it helps!

7 0
3 years ago
Read 2 more answers
1 3/7 x 2 3/4<br> fraction plz
maksim [4K]

Answer:

\frac{55}{14}

Step-by-step explanation:

First, we convert the mixed numbers into improper fractions: 1\frac{3}{7} =\frac{10}{7}, and 2\frac{3}{4}=\frac{11}{4}. Now, we multiply the fraction using the multiplication rule, \frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}: \frac{10}{7} \times \frac{11}{4} = \frac{110}{28} = \frac{55}{14}.

Thus, the product of the two given fractions is 55/14.

7 0
3 years ago
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