Answer:
Answer for the question:
The Rockwell hardness of a metal is determined by impressing a hardened point into the surface of the metal and then measuring the depth of penetration of the point. Suppose the Rockwell hardness of a particular alloy is normally distributed with mean 69 and standard deviation 2.7.
a. If a specimen is acceptable only if its hardness is between 67 and 75, what is the probability that a randomly chosen specimen has an acceptable hardness?
b. If the acceptable range of hardness is (69-C, 69+C), for what value of C would 95% of all specimens have acceptable hardness?
c. If the acceptable range is as in part (a) and the hardness of each of ten randomly selected specimens is independently determined, what is the expected number of acceptable specimens among the ten?
d. What is the probability that at most eight of ten independently selected specimens have a hardness of less than 72.84(HINT Y=number among the ten specimens with hardness less than72.84 is a binomial variable; what is p?)
is given in the attachment.
Step-by-step explanation:
Answer: Thanks bro
Step-by-step explanation:
Dino nuggies!
Answer:
Rs 85
Step-by-step explanation:
Cost of 5kgs of rice = Rs 425
Cost of 1 kg of rice = 425/5
= Rs 85
So, the cost of a kg of rice is Rs 85
Answer:
Read the explanation down
Step-by-step explanation:
This is a linear equation, because the equation does not have any exponents. Graph it by putting the equation into either slope-intercept form y=mx+b or point-slope form y−y1=m(x−x1).
Isolate y by first adding 6x to each side:
9y=6x−18
Divide each side by 9:
y=23x−2
Now graph the line y=23x−2 by first plotting the y intercept at (0,−2), then connecting points with a slope of 23.
graph{2/3x-2 [-10, 10, -5, 5]}