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3 years ago

Wuts the solution too this problem... 6a+7=13+7a

Mathematics

2 answers:

Lera25 [3.4K]3 years ago

5 0

Answer:

a=-6

Step-by-step explanation:

6a+7=13+7a

subtract 7 from both sides

6a=13+7a-7

subtract 7a from both sides

6a-7a=13-7

add like terms

-a=6

divide by -1

a=-6

Mila [183]3 years ago

3 0

Answer:

a= -6

Step-by-step explanation:

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3 years ago

What is the the area of the triangle in the composite figure above?

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Answer:

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Step-by-step explanation:

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3 years ago

36 is _______% less than 60? 24% 40% 60% 67%

ioda

40%less You take 36/60 That equals 60% This means that 36 is 60% of 60 So in 24 is 40% of 60 or 36 is 40% less than 60

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3 years ago

Read 2 more answers

Jessica had 140 to spend on 8 books. After buying them she had 12 dollars. How much did each book cost?

Rashid [163]

Answer:

each book was $16

Step-by-step explanation:

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hope this helps!

8 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Tomtit [17]

Apparently my answer was unclear the first time?

The flux of F across S is given by the surface integral,

$\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S$

Parameterize S by the vector-valued function r(u, v) defined by

$\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2. Then the surface element is

dS = n • dS

where n is the normal vector to the surface. Take it to be

$\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}$

The surface element reduces to

$\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\implies\mathbf n\,\mathrm dS=-49(\cos u\sin^2v\,\mathbf i+\sin u\sin^2v\,\mathbf j+\cos v\sin v\,\mathbf k)\,\mathrm du\,\mathrm dv$

so that it points toward the origin at any point on S.

Then the integral with respect to u and v is

$\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S=\int_0^{\pi/2}\int_0^{\pi/2}\mathbf F(x(u,v),y(u,v),z(u,v))\cdot\mathbf n\,\mathrm dS$

$=\displaystyle-49\int_0^{\pi/2}\int_0^{\pi/2}(7\cos u\sin v\,\mathbf i-7\cos v\,\mathbf j+7\sin u\sin v\,\mathbf )\cdot\mathbf n\,\mathrm dS$

$=-343\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}\cos^2u\sin^3v\,\mathrm du\,\mathrm dv=\boxed{-\frac{343\pi}6}$

4 0

3 years ago