Answer:
see below
Step-by-step explanation:
1. 10/16=5/6
2.14/63=2/9
3.6/14= 3/7
4.6/24= 1/3
5.7/70=1/10
6.5/10=1/2
7. 9/27= 1/3
8.6/72=1/12
9.6/27=1/3
10. 14/35= 2/5
11.12/24= 1/2
12.5/40=1/8
13.36/40=9/10
14.28/35=4/5
Given:
The graph of a function .
To find:
The interval where .
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for and .
The function between x=0 and x=3.6 lies below the x-axis. So, for .
Now,
For , the graph of h(x) is above the x-axis. So, .
For , the graph of h(x) is below the x-axis. So, .
For , the graph of h(x) is below the x-axis. So, .
Only for the interval , we get .
Therefore, the correct option is A.
The answer is amortization