I think january or december
Answer:
-15
Step-by-step explanation:
start from the inside and go out.
So first plug in -3 into g(x)
g(-3) = -3 - 7 = -10
then plug in -10 into f(x)
f(-10) = 2(-10) + 5 = -15
so f(g(x)) = -15
About 102.5625... I think
Class A: 6v + 8b = 202
Class B: 12v + 16b = 284
Solve using the elimination method:
since 6v and 12v are perfect for elimination, multiply the class A equation by 2 so that the van variable cancels out:
12v + 16b = 404
12v + 10b = 284
Then subtract the bottom equation from the top:
6b = 120
b = 20
Now you know that each bus can hold 20 students.
Just plug this into one of the original equations to solve for vans:
6v + 8(20) = 202
6v + 160 = 202
6v = 42
v=7
So then you know that each van can hold 7 students.
Check:
12 (7) + 10 (20) = 284
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<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>
Given coordinates to us are ,
- P(2,3) .
- Q(3,4).
- R(5,6)
- S(4,5)
Here it is asked to Prove that these are vertices of Rhombus . So we know that all sides of a Rhombus are equal .So if we show that value of all sides lenght are equal , then it will be a Rhombus .
We will use Distance Formula .
Now , here ,
<u>Dista</u><u>nce</u><u> </u><u>betwe</u><u>en</u><u> </u><u>P</u><u> </u><u>and</u><u> </u><u>Q</u><u> </u><u>:</u>
⇒ x = √ (2 - 3)² + (3-4)² .
⇒ x = √ (-1)² + (-1)² .
⇒ x = √ 1 + 1 .
⇒ x = √2 .
<u>Dista</u><u>nce</u><u> </u><u>betwee</u><u>n</u><u> </u><u>Q</u><u> </u><u>and</u><u> </u><u>S</u><u> </u><u>:</u>
⇒ x =√ [ (3-4)² + (5-4)².
⇒x = √ 1² + 1² .
⇒ x = √ 1 + 1 .
⇒ x = √2 .
Similarly we can prove other distances equal.