All categories

3 years ago

-6/5k=12 what is k? please explain

Mathematics

2 answers:

alekssr [168]3 years ago

8 0

Answer:

-10

Step-by-step explanation:

If ita

(-6/5)k = 12

k = 12 × 5/(-6)

k = 12 × -5/6

k = 2 × -5

k = -10

pentagon [3]3 years ago

3 0

Answer:.......

Step-by-step explanation:

You might be interested in

Need help ASAP! Tysm will mark brainliest

Vikki [24]

Answer:

80 inches

Step-by-step explanation:

Formula: 2l + 2w = perimeter

4 0

2 years ago

If Frances can paint 1/3 of a wall in 20 minutes, how long will it take her to paint a room with 4 walls.

charle [14.2K]

Answer:

1/3 is 20

4 is x

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Sodium hydroxide (NaOH) and hydrochloric acid (HCl) react to form sodium chloride (NaCl) and water according to the equation:

denpristay [2]

Answer:

0.00496

Step-by-step explanation:

e2020

6 0

2 years ago

Read 2 more answers

A rectangular table is positioned in a 10-foot by 10-foot<br> room as shown.

Greeley [361]

Answer:joe

Step-by-step explanation:

8 0

3 years ago

Any 10th grader solve it <br>for 50 points

kkurt [141]

Answer:

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$ is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., $a_{1}=A$ and common difference=D

The nth term can be written as

$a_{n}=A+(n-1)D$

pth term of given arithmetic progression is a

$a_{p}=A+(p-1)D=a$

qth term of given arithmetic progression is b

$a_{q}=A+(q-1)D=b$ and

rth term of given arithmetic progression is c

$a_{r}=A+(r-1)D=c$

We have to prove that

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0$

Now to prove LHS=RHS

Now take LHS

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)$

$=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)$

$=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)$

$=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}$

$=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}$

$=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}$