Plz help me out with these problems.

What's 2 to the negative 6 power times 2 to the negative 10th power

mafiozo [28]

When multiplying numbers with exponents, add the exponents.

So the answer is 2^-16

7 0

2 years ago

Present Value Hoew much shuold be deposited in an account paying 7.8% interest compounded monthly in order to have a balance of

Alisiya [41]

Answer: $15385 should be deposited.

Step-by-step explanation:

The principal was compounded monthly. This means that it was compounded 12 times in a year. So

n = 12

The rate at which the principal was compounded is 7.8%. So

r = 7.8/100 = 0.078

It was compounded for 4 years. Therefore,

t = 4

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. The total amount is given as $21000. Therefore

21000 = P (1+0.078/12)^12×4

21000 = P (1+0.078/12)^48

21000 = P (1+0.0065)^48

21000 = P (1.0065)^48

P = 21000/1.365

P = $15385

6 0

2 years ago

2. In a relationship between variables, what is the variable called that changes in response to

valkas [14]

Answer:

A dependent variable

Step-by-step explanation:

is a variable whose value will change depending on the value of another variable, called the independent variable. Dependent variables are also known as outcome variables, left-hand-side variables, or response variables.

4 0

2 years ago

If f(x) = x + 3 and g(x) = -7x + 7, which statement is true? Click on the correct answer. 5 is in the domain of fºg. 5 is not in

Studentka2010 [4]

Answer:

man you got this

Step-by-step explanation:

If f(x) = x + 9 and g(x) = 9x – 4, - 22024651. ... Click on the correct answer. 3 is not in the domain of fºg. 3 is in the domain of fºg. 1. See answer. Add answer+5 pts ... Answer: 3 is in the domain of f(g(x)). Step-by-step explanation: ... What is the domain of the given function? a) {x | x = –6, –1, 0, 3}; {y | y = –7, –2, ...

The domain is all real numbers except 9 (positive)

This is because we can't have 0 in the denominator, and when x equals 9, then the denominator is 0. Anything divided by 0 is undefined, which is why 9 (in this equation) is not included.

3 0

3 years ago

Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin

Artemon [7]

"Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find $\bar{d}$ , $s_{d}$ , the t-test statistic, and the critical values to test the claim that $\mu_{d} = 0$ "

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find $\bar{d}$
You are asked to find the mean difference between the two variables, which is given by the formula:
$\bar{d} = \frac{\sum (x - y)}{n}$

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example:
 $\bar{d} = \frac{6}{8} = 0.75$ 

B) Find $s_{d}$
You are asked to find the standard deviation, which is given by the formula:
 $s_{d} = \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }$

These are the steps to follow:
1) Subtract the mean difference from each pair's difference
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
$s_{d} = \sqrt{ \frac{101.5}{8-1} }$
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
$t = \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}$

where SE = standard error is given by the formula:
$SE = \frac{ s_{d} }{ \sqrt{n} }$

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract $\mu_{d}$
6) divide by the standard error

In our example:
SE = 3.81 / √8
= 1.346

The problem gives us $\mu_{d} = 0$ , therefore:
t = [(9.75 - 9) - 0] / 1.346
= 0.56

D) Find $t_{\alpha / 2}$
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find $t_{\alpha / 2} = 1.895$ 

Since our t-value is less than $t_{\alpha / 2}$ we can reject our null hypothesis!!

7 0

3 years ago