the strength of students in a school when increased by 8% becomes 2160. find the original strength of students in the school.
1 answer:
Answer:
1987.2
Step-by-step explanation:
We can write a proportion to find the total amount in the choir using the information given. A proportion is two equivalent ratios set equal to each other. Since we know the strength of students increased by 8% to 2160 then the original was 92%.
We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.
92(2160)=100(y)
198720=100y
y=1987.2
There are 1987.2 as the original strength of students.
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Answer:
88.51 is the minimum score needed to receive a grade of A.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 73
Standard Deviation, σ = 11
We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.0793.
Calculation the value from standard normal z table, we have,
Hence, 88.51 is the minimum score needed to receive a grade of A.
Answer:
The value of a is 10.
Step-by-step explanation:
We are given with the following pair of the linear system of equations below;
and
.
Also, the solution is given as (a, -1).
To find the value of 'a', we have to substitute the solution in the equation because it is stated that (a, -1) is the solution of the given two equations.
So, the x coordinate value of the solution is a and the y coordinate value of the solution is (-1).
First, taking the equation;
Put the value of x = a and y = -1;
(-1) = -(a) + 9
a = 9 + 1 = 10
Now, taking the second equation;
Put the value of x = a and y = -1;
0.5a = 6 - 1
0.5a = 5
a = 10
Since we get the value of a = 10 from the equations, so the value of a is 10.