the strength of students in a school when increased by 8% becomes 2160. find the original strength of students in the school.
1 answer:
Answer:
1987.2
Step-by-step explanation:
We can write a proportion to find the total amount in the choir using the information given. A proportion is two equivalent ratios set equal to each other. Since we know the strength of students increased by 8% to 2160 then the original was 92%.
We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.
92(2160)=100(y)
198720=100y
y=1987.2
There are 1987.2 as the original strength of students.
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Answer:
Option (2).
Step-by-step explanation:
In the figure attached,
A, C and B are the points lying on a straight line.
2 lines EC and DC have been drawn by extending the lines from C to E and D respectively.
Ray CE is the angle bisector of ∠ACD.
That means CE divides ∠ACD in two equal parts.
m∠ACE = m∠DCE
Since m∠ACD = m∠ACE + m∠DCE
= 2(m∠ACE)
m∠ACE =
Therefore, option (2) will be the answer.
