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blsea [12.9K]
3 years ago
8

the strength of students in a school when increased by 8% becomes 2160. find the original strength of students in the school.

Mathematics
1 answer:
Leni [432]3 years ago
6 0

Answer:

1987.2

Step-by-step explanation:

We can write a proportion to find the total amount in the choir using the information given. A proportion is two equivalent ratios set equal to each other. Since we know the strength of students increased by 8% to 2160 then the original was 92%.

\frac{92}{100}=\frac{y}{2160}

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.

92(2160)=100(y)

198720=100y

y=1987.2

There are 1987.2 as the original strength of students.


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Answer:

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Step-by-step explanation:

We are asked to find the value of A. We know from the question that we need to have the sum of -3x and (A)x equal the third term of the original polynomial, which is 2x. written out in an equation, it looks like this.

-3x+(A)x=2x

We can simplify the equation if we add 3x to both sides, which then leaves us with this.

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We can further simplify the equation by dividing both sides by x. This leaves us with our last equation for this problem.

A=5

Finally, we have our answer. We can also verify that this is a valid integer by multiplying our, now completed, quotient by the divisor and adding the remainder, which in this case, our remainder is 0, so we will not be including it in our operation.

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If our calculations were all correct, the product of these polynomials should equal our dividend, verifying our integer is valid; lo' and behold, it is.

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<h3>Keys features of a quadratic graph</h3>

The key features are the x-intercepts, y-intercepts, axis of symmetry, and the vertex.

If we add units we can move this function upwards, downwards leftwards and rightwards.

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