Answer:
1. Option (a) is the correct answer. "Place a firewall between the Internet and your Web server".
2. Option (e) is the correct answer. "Require encryption for all traffic flowing into and out from the Ken 7 Windows environment".
3. Option (d) is the correct answer. "Implement Kerberos authentication for all internal servers".
4. The correct answer is option (g) "Require all personnel attend a lunch and learn session on updated network security policies".
5. Option (c) is the correct answer. "Enforce password complexity".
Explanation:
1. Users who tried to use ken 7 network resources for social media access will not be enable to do so.
2. Encryption for inflow and outflow of traffic from Ken 7 windows environment will monitor any personal devices which is connected to Ken 7 windows network.
3. The implementation of Kerberos authentication will deny anonymous users access to protected resources in Ken 7 infrastructure.
4.All personnel will be taught the network policies to avoid sending report to unsecured printers.
5. The more complex passwords are, the more secured the server will be. A complex password should be enforce for network security.
Answer:
In computing, extract, transform, load (ETL) is the general procedure of copying data from one or more sources into a destination system which represents the data differently from the source(s) or in a different context than the source(s).
Data extraction involves extracting data from homogeneous or heterogeneous sources; data transformation processes data by data cleansing and transforming them into a proper storage format/structure for the purposes of querying and analysis; finally, data loading describes the insertion of data into the final target database such as an operational data store, a data mart, data lake or a data warehouse. Hope this helps! PLEASE GIVEE ME BRAINLIST!!! =)
Answer:
def leap_year(y):
if y % 4 == 0:
return 1
else:
return 0
def number_of_days(m,y):
if m == 2:
return 28 + leap_year(y)
elif m == 1 or m == 3 or m == 5 or m == 7 or m == 8 or m ==10 or m == 12:
return 31
elif m == 4 or m == 6 or m == 9 or m == 11:
return 30
def days(m,d):
if m == 1:
return 0 + d
if m == 2:
return 31 + d
if m == 3:
return 59 + d
if m == 4:
return 90 + d
if m == 5:
return 120 + d
if m == 6:
return 151 + d
if m == 7:
return 181 + d
if m == 8:
return 212 + d
if m == 9:
return 243 + d
if m == 10:
return 273 + d
if m == 11:
return 304 + d
if m == 12:
return 334 + d
def days_left(d,m,y):
if days(m,d) <= 60:
return 365 - days(m,d) + leap_year(y)
else:
return 365 - days(m,d)
print("Please enter a date")
day=int(input("Day: "))
month=int(input("Month: "))
year=int(input("Year: "))
choice=int(input("Menu:\n1) Calculate the number of days in the given month.\n2) Calculate the number of days left in the given year.\n"))
if choice == 1:
print(number_of_days(month, year))
if choice == 2:
print(days_left(day,month,year))
Explanation:
Hoped this helped
Answer: Protocol identifier
Explanation:
Just took the test and resource name was incorrect. Hope this helps :)
