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gladu [14]
3 years ago
11

How many digits are written when 1000 to the power of 2015 is expressed as a numeral?

Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0

Answer: There are 6046 digits will be written on expansion upto 2015th power.

Step-by-step explanation:

Since we have given that

1000^{2015}

We have to find the number of digits ,

So,

1000^{2015}\\\\=(10^3)^{2015}\\\\=10^{6045}

Since we know that

10^n\text{ has n+1 number of digits }

so,

10^{6045}\text{ has 6046 number of digits }

Hence, there are 6046 digits will be written on expansion upto 2015th power.

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Naya [18.7K]

x=23

Simplifying

(3x + -50) + (7x)

Reorder the terms:

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Remove parenthesis around (-50 + 3x)

-50 + 3x + (7x) =

Combine like terms: 3x + (7x)

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Solving

-50 + 10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '50' to each side of the equation.

-50 + 50 + 10x = 180 + 50

Combine like terms: -50 + 50 = 0

0 + 10x = 180 + 50

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Divide each side by '10'.

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Plug in the points:

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