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gladu [14]
3 years ago
11

How many digits are written when 1000 to the power of 2015 is expressed as a numeral?

Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0

Answer: There are 6046 digits will be written on expansion upto 2015th power.

Step-by-step explanation:

Since we have given that

1000^{2015}

We have to find the number of digits ,

So,

1000^{2015}\\\\=(10^3)^{2015}\\\\=10^{6045}

Since we know that

10^n\text{ has n+1 number of digits }

so,

10^{6045}\text{ has 6046 number of digits }

Hence, there are 6046 digits will be written on expansion upto 2015th power.

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AveGali [126]

Answer:

f = 65

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Step-by-step explanation:

Given the equation : 201.50=f+6.50(21)

Solving for f:

201.50 = f + 136.50

201.50 - 136.50 = f

f = 65

The equation above is written in the form a slope intercept function where,, 6.50 is the gradient and X equals the number of shirts, The total cost of printing is 201.50

f is the intercept and represents the initial fee or setup cost. Hence, the setup. Cost = 65

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Evaluate each expression using the values m = 7, r = 8, and t = 2.
user100 [1]

So I'll walk through the first 2. Then please try the other ones and let me know if you run into more problems.

5m-6

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5(7)-6

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So that was the first one.

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We just do what we do with the first problem.

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---

hope it helps

p.s. When there is subtraction, add. When there is division, multiply to cancel that out. When there is multiplication, divide to cancel. etc.

6 0
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Read 2 more answers
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grandymaker [24]

Answer:

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Step-by-step explanation:

you can divide the second term by the first term to solve

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