What is the sum of the arithmetic series: s10 = -20, d = 4, a1 =?
2 answers:
<h2>
Step-by-step explanation:</h2><h3>

Given</h3>
s10 = -20
n = 10
an = -20
solution
s10 = n\2 [a+(n-1)d]
-20 = 10a2[a+(10-1)4]
-4 = a +36
a1 = -40

Hope it helps.
Hope it helps
Answer:
first term a1 is -40.
Step-by-step explanation:
in an arithmetic series,
sum of first term terms (S10) = -20
Common difference (d) = 4
first term (a)= ?
number of terms (n)= 10
now,
S10 =( n÷2) [a1 +(n-1) d]
or, -20 = (10÷2) [a1 + (10-1) 4]
or, -20 = 5 ( a1 + 36)
or, -4 = a1 + 36
or, a1 = -40
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Hope it helps :)
The answer would be b A≈1636.8
The gcf of both is 11 so it would be 9+4q
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Step-by-step explanation:
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