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Marina86 [1]
3 years ago
12

What is the sum of the arithmetic series: s10 = -20, d = 4, a1 =? ​

Mathematics
2 answers:
Otrada [13]3 years ago
8 0
<h2>Step-by-step explanation:</h2><h3>\green\star Given</h3>

\blue\stars10 = -20

\blue\starn = 10

\blue\star an = -20

\green\star solution

\green\stars10 = n\2 [a+(n-1)d]

\green\star-20 = 10a2[a+(10-1)4]

\green\star-4 = a +36

\green\stara1 = -40

\small\boxed{a = -40}

Hope it helps.

Hope it helps

KengaRu [80]3 years ago
4 0

Answer:

first term a1 is -40.

Step-by-step explanation:

in an arithmetic series,

sum of first term terms (S10) = -20

Common difference (d) = 4

first term (a)= ?

number of terms (n)= 10

now,

S10 =( n÷2) [a1 +(n-1) d]

or, -20 = (10÷2) [a1 + (10-1) 4]

or, -20 = 5 ( a1 + 36)

or, -4 = a1 + 36

or, a1 = -40

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