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3 years ago

How do you solve shaded areas

Mathematics

1 answer:

marissa [1.9K]3 years ago

4 0

If it is rectangular or square then just multiply the length x width and you get the area (shaded area)

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Solve for x<br> 7x−4≤6<br><br> Give your answer as an improper fraction in its simplest form.

pashok25 [27]

Answer:

X≤10/7

Step-by-step explanation:

7x-4≤6

add 4 both sides

7x-4+4≤6+4

7x≤10

divide 7 both sides

7x/7≤10/7

x≤10/7

hope it's helpful ❤❤❤❤

THANK YOU.

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3 years ago

a museum has 13486 butterflies, 1856 ants, and 13859 beetles. what is the order of the insects from least number to greatest num

k0ka [10]

1856 13,486 13,859
Ants, butterflies, beetles
Just look for the smallest number out of the three and then the smallest out of the two left, like 10,2,20. 2, 10, 20

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3 years ago

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What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE

Nutka1998 [239]

Answer:

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),$ $\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

Step-by-step explanation:

Let points D, E and F have coordinates $(x_D,y_D),\ (x_E,y_E)$ and $(x_F,y_F).$

1. Midpoint M of segment DF has coordinates

$\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).$

2. Midpoint N of segment EF has coordinates

$\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).$

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

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3 years ago

-69=-3m-2(5m+2) help me solve plssss

sasho [114]

$-3m-2(5m+2)=-69\ \ \ |\text{use distributive property}\\\\-3m-2(5m)-2(2)=-69\\\\-3m-10m-4=-69\\\\-13m-4=-69\ \ \ \ |+4\\\\-13m=-65\ \ \ \ \ |:(-13)\\\\\boxed{m=5}$

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4 years ago

ANSWER QUICK I ONLY HAVE A WEEK BOEFORE I FAIL PLEASE ANSWER PIC IS THE QUESTION

deff fn [24]

Answer:

theres no picture

Step-by-step explanation:

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3 years ago

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