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Shalnov [3]
3 years ago
13

What mass of Na2SO4 is needed to make 2.0 L of 3.0 M solution (Na = 23 g; S = 32 g; O = 16 g)

Chemistry
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer: 710.5g

Explanation:

Moles of Na2SO4 = conc. x volume(dm3)

= 2 x (2500cm3/1000)

= 5 mol

Mass of Na2SO4 = moles x molar mass

= 5 x ((23 x 2) + 32.1 + (16 x 4))

= 710.5g

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What is the nuclear binding energy of an atom that has a mass defect of 5.0446
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Answer:

<em>Option C: 4.54 x </em>10^{11}<em> KJ/mol of nuclei</em>

<em>Note: </em>Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}.

Explanation:

If mass defect is known, then nuclear binding energy can easily be calculated, here's how:

First step is to convert that mass defect into kg.

Mass defect = 5.0446 amu

Mass defect = 5.0466 x 1.6606 x 10^{-27}

Because 1 amu = 1.6606 x 10^{-27} Kg.

<em>Mass defect = 8.383 x </em>10^{-27}<em> kg.</em>

Now, we need to find out it's energy equivalent by using following equation:

Using the equation E = mc²:

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E = (8.383 x 10^{-27}) x (3.00 x 10^{8})²

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(7.54 x 10^{-10} Joule/nucleus)x(1 kJ/1000 Joule)x(6.022 x 10^{23} nuclei/mol) =  

<em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em>

E = <em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em> So, this is the nuclear binding energy of that atom, which is option  C.

<em>Note:</em> Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}

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