Answer:
hyaluronic phosphoric acid
<span>they are much bigger because </span><span>equilibrium constant shows ratio of </span><span>concentrations of the reactants to the equilibrium concentration of the product.</span>
Answer:
9.07 L
Explanation:
<em>Calculate the volume occupied at s.t.p by 6.89 g of NH₃ gas [H = 1.0, N = 14.0].</em>
Step 1: Given and required data
- Molar mass of NH₃ (M): 17.0 g/mol
Step 2: Calculate the moles (n) of NH₃
We will use the following epxression.
n = m / M
n = 6.89 g / (17.0 g/mol) = 0.405 mol
Step 3: Calculate the volume occupied by 0.405 moles of NH₃ at STP
At STP, 1 mole of NH₃ occupies 22.4 L (assuming ideal behavior).
0.405 mol × 22.4 L/1 mol = 9.07 L
Answer:
Carbon Prefix Structure
1 Methane CH4
2 Ethane CH3CH3
3 Propane CH3CH2CH3
4 Butane CH3(CH2)2CH3
5 Pentane CH3(CH2)3CH3
6 Hexane CH3(CH2)4CH3
7 Heptane CH3(CH2)5CH3
8 Octane CH3(CH2)6CH3
9 Nonane CH3(CH2)7CH3
10 Decane CH3(CH2)8CH3
11 Undecane CH3(CH2)9CH3
12 Dodecane CH3(CH2)10CH3
Explanation:
