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Vaselesa [24]
3 years ago
10

1.4 moles of propane react with 16 moles of oxygen gas in a combustion reaction, how many moles of carbon dioxide is formed whic

h is the limiting reagent?
Chemistry
1 answer:
Liula [17]3 years ago
7 0
Answer is: 9.6 <span>moles of carbon dioxide is formed and oxygen is limiting reagent.

Balanced chemical reaction: C</span>₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
n(C₃H₈) = 4 mol; a
n(O₂) = 16 mol; limiting reagent.
From balanced chemical reaction: n(C₃H₈) : n(O₂) = 1 : 5.
For 4 moles of propane, 20 moles of oxygen is needed.
n(O₂) : n(CO₂) = 5 : 3.
n(CO₂) = 3 · 16 mol ÷ 5.
n(CO₂) = 9.6 mol.
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To make a 2 M solution of calcium chloride (CaCl2), you would place how many grams of CaCl2 into a container and then add how mu
belka [17]

Answer:

For a volume of 1 liter, we have a total mass of 220 grams of CaCl2 ( Option A)

Explanation:

<u>Step 1: </u>Given data

The concentration of the solution we want to make is 2M

2M = 2 moles/ L So the volume = 1L

The molar mass of CaCl2 is = 40 + 2*35 = 110g/mole

<u>Step 2:</u> Calculate number of moles

If we consider the volume = 1 L then for a concentration of 2M, this means the number of moles is 2

<u>Step 3:</u>  Calculate mass

The molar mass of CaCl2 = 110 g/mole

This means 110 grams per 1 mole

for 2 moles the mass is 220 grams

This means that for a volume of 1 liter, we have a total mass of 220 grams of CaCl2

6 0
3 years ago
How is a suspension different from a colloid?
Mashcka [7]

Answer:

Explanation:

Colloidal:

  • Colloid consist of the particles having size between 1 - 1000 nm i.e, 0.001- 1μm.  
  • The particles in colloid can not be seen through naked eye.
  • It is homogeneous.
  • We can not separate the colloidal through the filtration. The pore size of filter paper is 2μm. However it can be separated through the ultra filtration. In ultra filtration the pore size is reduced by soaking the filter paper in gelatin and then in formaldehyde. This is only in case of when solid colloidal is present, if colloid is liquid , there is no solid particles present and ultra filtration can not be used in this case.

Suspension:

  • The particle size in suspension is greater than 1000 nm.
  • These particles can seen through naked eye.
  • It is heterogeneous.  
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3 0
3 years ago
True or False: The first part of an organism’s scientific name is its genus and the second part is its species.
castortr0y [4]

It is True :)

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4 0
4 years ago
Please answer ASAP I’ll give the brainliest!
lilavasa [31]

1. 1 mol=6.02.10²³ particles

\tt \dfrac{3.63\times 10^{23}}{6.02\times 10^{23}}=0.602~moles

2. Molar mass = Total atomic mass of component

AlBr₃ = Ar Al + 3. Ar Br

AlBr₃ = 27 + 3. 80 = 267 g/mol

3. mass = mol x MW

MW MnCl₂  = 55 + 2.35.5=126 g/mol

mass = 31.6 x 126 =3981.6 g

4. at STP, 1 mol =22.4 L, so for 5.6 L :

\tt \dfrac{5.6}{22.4}=0.25~moles

5. moles = mass : MW

MW CH₃OH = 12.1 + 4. 1 + 16.1 =32 g/mol

\tt moles=\dfrac{0.5}{32}=0.016

6. 1 mol = 22.4 L at STP

1 mol = 6.02.10²³ particles

moles for  8.20 x 10¹⁴ molecules

\tt \dfrac{8.2\times 10^{14}}{6.02\times 10^{23}}=1.36\times 10^{-9}

volume :

\tt 1.36\times 10^{-19}\times 22.4=3.05\times 10^{-8}~L

4 0
3 years ago
Hardness of metals can be decreased by: (a) adding interstitial alloying elements (b) making glassy metals through extremely hig
n200080 [17]

Answer:

Option c is correct

Explanation:

The interstitial alloy elements occupy the free spaces in the metal structure and improve the symmetry of the crystalline network, for this reason this type of elements increases the hardness of the metal.

Vitreous metals are called that because they are formed by high cooling rates and form amorphous structures such as glass, such structures contain packaging of atoms of different sizes, which decreases the free spaces in the metal structure and this increases their hardness.

In option d, the work at low temperatures causes the vibrations of the atoms to decrease and compact, this makes many metals brittle but in general increases their hardness.

Option c is correct because in annealing the metal is heated to the austenization temperature, that is, the temperature at which a structural change occurs, which destroys its crystalline network and then slowly cools to maintain this structure change and by causing this disorder, the spaces between the atoms increase and the hardness of the metal decreases.

4 0
3 years ago
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