Answer:
For a volume of 1 liter, we have a total mass of 220 grams of CaCl2 ( Option A)
Explanation:
<u>Step 1: </u>Given data
The concentration of the solution we want to make is 2M
2M = 2 moles/ L So the volume = 1L
The molar mass of CaCl2 is = 40 + 2*35 = 110g/mole
<u>Step 2:</u> Calculate number of moles
If we consider the volume = 1 L then for a concentration of 2M, this means the number of moles is 2
<u>Step 3:</u> Calculate mass
The molar mass of CaCl2 = 110 g/mole
This means 110 grams per 1 mole
for 2 moles the mass is 220 grams
This means that for a volume of 1 liter, we have a total mass of 220 grams of CaCl2
1. 1 mol=6.02.10²³ particles

2. Molar mass = Total atomic mass of component
AlBr₃ = Ar Al + 3. Ar Br
AlBr₃ = 27 + 3. 80 = 267 g/mol
3. mass = mol x MW
MW MnCl₂ = 55 + 2.35.5=126 g/mol
mass = 31.6 x 126 =3981.6 g
4. at STP, 1 mol =22.4 L, so for 5.6 L :

5. moles = mass : MW
MW CH₃OH = 12.1 + 4. 1 + 16.1 =32 g/mol

6. 1 mol = 22.4 L at STP
1 mol = 6.02.10²³ particles
moles for 8.20 x 10¹⁴ molecules

volume :

Answer:
Option c is correct
Explanation:
The interstitial alloy elements occupy the free spaces in the metal structure and improve the symmetry of the crystalline network, for this reason this type of elements increases the hardness of the metal.
Vitreous metals are called that because they are formed by high cooling rates and form amorphous structures such as glass, such structures contain packaging of atoms of different sizes, which decreases the free spaces in the metal structure and this increases their hardness.
In option d, the work at low temperatures causes the vibrations of the atoms to decrease and compact, this makes many metals brittle but in general increases their hardness.
Option c is correct because in annealing the metal is heated to the austenization temperature, that is, the temperature at which a structural change occurs, which destroys its crystalline network and then slowly cools to maintain this structure change and by causing this disorder, the spaces between the atoms increase and the hardness of the metal decreases.