The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.

The mean of the sampling distribution of sample proportion is, $\hat p$ .

One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Given:

n = 150

$\hat p$ = 0.68

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.68\pm1.96\sqrt{\frac{0.68(1-0.68)}{150}}\\\\=0.68\pm 0.0747\\\\=(0.6053, 0.7547)\\\\\approx (0.61, 0.75)$

Thus, the reasonable range for the population mean is (61%, 75%).

5 0

4 years ago

Why is looking at cash flow an important step in a good financial plan?

sergejj [24]

Cuz it can help you later on in the fuchure

8 0

3 years ago

I only need help with the second part of this question. please can you help?

matrenka [14]

13,822 to one significant figure is 10,000

623 to one significant figure is 600

14 to one significant figure is 10

10,000 times 600 = 6,000,000

6,000,000/10 = 600,000

4 0

3 years ago

Find the perimeter of a rectangle with length 7x - 2 and width 5x^2 + 1.

stealth61 [152]

Answer:

10x^2 + 14x - 2

Step-by-step explanation:

So for the perimeter, you have to solve 2(7x-2) + 2(5x^2+1)

So distribute the 2s on both s we get 14x - 4 + 10x^2 + 2

This in standard form is 10x^2 + 14x - 2

4 0

3 years ago