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Sloan [31]
3 years ago
5

Two people agree to meet for a drink after work but they are impatient and each will wait only 15 minutes for the other person t

o show up. Suppose that they each arrive at independent random times uniformly distributed between 5 p.m. and 6 p.m. What is the probability they will meet?
Mathematics
1 answer:
Nostrana [21]3 years ago
6 0

Answer: 50% is the probability

Step-by-step explanation:

There are to people showing up at to different times now the probability is out of a 100%.

So 100 divided by 2 will equal to a 50

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Which quadratic function has a leading coefficient of 2 and a constant term of –3?
Romashka [77]
The answer is <span>f(x) = 2x2 + 3x – 3
</span>
f(x) = ax² + bx + c
a - the leading coefficient
c - the constant term

<u>We are looking for a = 2, c = -3</u>

Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.

In the function: <span>f(x) = –3x2 – 3x + 2
</span>a = -3
c = 2

In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3
6 0
3 years ago
Read 2 more answers
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Free_Kalibri [48]
So, you know that there were 5 people there, Kara and 4 friends. To divide equally, just divide 42.30 by 5=

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Hope this helps!!
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3 years ago
Its the last one:) please help. giving brainlist
diamong [38]

Answer:

5

Step-by-step explanation:

Segments are named by their endpoints. Therefore, segment PQ will have endpoints P and Q. The length of the segment is equal to the distance between these points.

To find the distance between P and Q given their coordinates, use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let:

P(-2, 7)\implies (x_1, y_1),\\Q(1, 3)\implies (x_2, y_2)

The distance between these points is equal to:

d=\sqrt{(1-(-2))^2+(3-7)^2},\\d=\sqrt{3^2+(-4)^2},\\d=\sqrt{9+16},\\d=\sqrt{25},\\d=\boxed{5}

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pshichka [43]
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For a geometric series to have a sum r^2<1

So that the normal sum....

s(n)=a(1-r^n)/(1-r)   becomes if r^2<1

s=a/(1-r)
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3 years ago
How many points need to be removed from this graph so that it will be a function?
leva [86]
You didn't add a graph lol
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