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lina2011 [118]
3 years ago
11

Which of these strategies would eliminate a variable in the system of equations? ​8x+8y=2 8x+5y=1 ​ Add the equations. (Choice B

) B Subtract the bottom equation from the top equation. (Choice C) C Multiply the top equation by 1/2,then subtract the bottom equation from the top equation.
Mathematics
2 answers:
harkovskaia [24]3 years ago
7 0

Answer:

B. Subtract the bottom equation from the top equation.

Step-by-step explanation:

When looking at the two equations:

8x + 8y = 2

8x + 5y = 1

We can easily get rid of the x variable by subtracting the two equations from each other since the terms are equivalent. This would allow us to solve for the y value, which we could plug into the an equation to solve for the x value.

Lady_Fox [76]3 years ago
6 0

Answer:

Subtract the bottom equation from the top equation.

Step-by-step explanation:

i made sure it was the answer which is in khan academy.

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Janet has three times as many dimes as nickels and twice as many quarters as nickels. If she has $5.10 in all, how many nickels,
Mama L [17]
If number of nickel = n
number of dimes = 3n
number of quarters = 2n

Amount of nickel = 5n
Amount of dimes = 30n
Amount of quaters = 50n

Total Amount = <span>5n + 30n + 50n = 510

In short, Your Answer would be Option C

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6 0
3 years ago
PLEASE HELP!! Using the SAS Congruence Theorem
Komok [63]

Answer:

SAS

Step-by-step explanation:

JK is congruent to LM   (given)

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What is the value of x in the equation (StartFraction one-half EndFractionx + 12) = StartFraction one-half EndFraction(StartFrac
anastassius [24]

Answer:

x =-24

Step-by-step explanation:

Given

(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3

Required

Solve for x

(\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3

Open all brackets

\frac{2}{3}*\frac{1}{2}x + \frac{2}{3}*12 = \frac{1}{2}*\frac{1}{3}x + \frac{1}{2}*14 - 3

\frac{2 * 1}{3 *2}x + \frac{2 * 12}{3}= \frac{1 * 1}{2 * 3}x + \frac{1 * 14}{2} - 3

\frac{1}{3}x + \frac{24}{3}= \frac{1}{6}x + \frac{14}{2} - 3

\frac{1}{3}x +8= \frac{1}{6}x + 7 - 3

Collect like terms

\frac{1}{3}x - \frac{1}{6}x =7 - 3 -8

\frac{1}{3}x - \frac{1}{6}x =-4

Solve fraction

\frac{2-1}{6}x =-4

\frac{1}{6}x =-4

Multiply both sides by 6

6 * \frac{1}{6}x =-4 * 6

x =-4 * 6

x =-24

8 0
3 years ago
How do you solve 163-x= -52
DanielleElmas [232]

163-x=-52

first subtract 163 and you get -215

now it looks like -x=-215

then the negative signs cancel out and its now x=215

5 0
3 years ago
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