4 years ago

16x squares + 7x squared

Mathematics

1 answer:

anyanavicka [17]4 years ago

5 0

Answer:

23x^2

Step-by-step explanation:

When adding variables, if they have the same exponent then all that needs to be done is add the constants. In this case both have x^2 so the answer is 23x^2. Hope this helps! :)

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5(x+3)(x+2)-3(x2+2x+1)

mr Goodwill [35]

[ Answer ]

$\boxed{5x^{2} \ + \ 13x \ + \ 27}$

[ Explanation ]

Simplify: 5(x + 3)(x + 2) - 3(x2 + 2x + 1)

--------------------------------------

Add Similar Elements: 2x + 2x = 4x

5(x + 3)(x + 2) - 3(4x + 1)

Expand: 5(x + 3)(x + 2) - 3(4x + 1): $5x^{2}$ + 25x + 30

$5x^{2}$ + 25x + 30 - 3(4x + 1)

Expand: - 3(4x + 1): -12x - 3

$5x^{2}$ + 25x + 30 - 12x - 3

Simplify: $5x^{2}$ + 25x + 30 - 12x - 3: $5x^{2}$ + 13x + 27

= $5x^{2}$ + 13x + 27

$\boxed{[] \ Eclipsed \ []}$

4 0

3 years ago

If y varies directly as x and y = 16 when x = 36 find y when x =54

11111nata11111 [884]

Answer:

Step-by-step explanation:

54/36=1.5

1.5*16=24

8 0

3 years ago

2) 62 - 46 +4 = 0 <br> quadratic formula

AleksandrR [38]

This does not need the quadratic formula since there are no variables to begin with:

62-46+4 = 0

20 = 0.

And 20 does not equal 0 so both sides aren't equal.

Soooo not much to do with this question.

4 0

3 years ago

Simplify the expression below (assuming x and y are non-zero numbers).

Yuri [45]

Answer: Option 2

Step-by-step explanation:

$\frac{15x^4y^-^2}{3x^2y^3}$

Divide 15 by 3 and substract the variables's exponents.

$5x^4^-^2y^-^2^-^3$

Solve;

$5x^2y^-^5$

$\frac{5x^2}{y^5}$

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3 years ago

Please help me im very depressed and im struggling a lot on my math and i really need some answers

Zarrin [17]

Answer:

its B. 0.0563 and 0.0564

7 0

3 years ago

Read 2 more answers