Answer:
18 credits if studying, if working this is usually monthly and does not reflect credit overload. Unless there are bank credit card payments to pay and normal charges.
Lets say charges are £20 a month and no student debt.
Plus 30 x monthly rent for annual proof for lettings. shows $30,000 credit worth + 15000 extra..
Average rent $1000 a month. = 12,000 45000-12000 = 33000 utility and necessary expenditure $3000 a year = $30,000.
Therefore debt can be considered long term payments at half this $15,000 p/y
or 7% of 45,000
7% = $3150 p/y / 12 = $262.5 p/m
with $11,850 of $30000 to be considered for credit worth + approval and interest in any 12 month term.
Should Terrance require low interest credit his worth thereafter if rent was low at $1000 a month, he would be considered for maximum $880 repayment terms for short term new loans.
Step-by-step explanation:
I don't think it really matters if there's a dash there or not
Answer:
The measure of angle B is 54°. The measure of angle A is 51°. The measure of angle AFE is 47°.
According to exterior angle theorem: It a triangle
Exterior angle = Sum of opposite interior angles
In triangle BED,
The measure of angle B is 54°.
In triangle ABC,
The measure of angle A is 51°.
In triangle AEF,
Using angle sum property,
Therefore the measure of angle AFE is 47°.
In order to know what the polygon is, you have to plot the coordinates. After plotting, it is obviously shown a form of a rectangle. After connecting the midpoints of the sides, it formed a (D) rhombus, not a kite.
Answer:
sorry if im wrong i think wrong numbers. plz check
Step-by-step explanation:
The center of dilation of the question is (-4,-3) .
let say that
x0=-4
y0=-3
Label the image A'B'C'
The new coordinate would be
A(-4,-1)
x=4
y=-1
x'=x0+ 2(x - x0)
x'= -4+ 2(-4 +4)
x'=-4
y'=y0+ 2(y - y0)
y'= -3+ 2(-1 +3)
y'=-3 +4= 1
______________________________
B(-4,-3)
x=-4
y=-3
x'=x0+ 2(x - x0)
x'= -4+ 2(-4 +4)
x'=-4
y'=y0+ 2(y - y0)
y'= -3+ 2(-3 +3)
y'=-3
______________________________
C(-1,-3)
x=-1
y=-3
x'=x0+ 2(x - x0)
x'= -4+ 2(-1 +4)
x'=-4 +6= 2
y'=y0+ 2(y - y0)
y'= -3+ 2(-3 +3)
y'=-3
A'(-4,1)
B'(-4,-3)
C'(2,-3)
