Answer:
g=3
Step-by-step explanation:
Answer: 1.3 is her interest rate hopefully I'm correct on this
Given Information:
Population mean = p = 60% = 0.60
Population size = N = 7400
Sample size = n = 50
Required Information:
Sample mean = μ = ?
standard deviation = σ = ?
Answer:
Sample mean = μ = 0.60
standard deviation = σ = 0.069
Step-by-step explanation:
We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10
np ≥ 10
50*0.60 ≥ 10
30 ≥ 10 (satisfied)
n(1 - p) ≥ 10
50(1 - 0.60) ≥ 10
50(0.40) ≥ 10
20 ≥ 10 (satisfied)
The mean of the sampling distribution will be same as population mean that is
Sample mean = p = μ = 0.60
The standard deviation for this sampling distribution is given by
![\sigma = \sqrt{\frac{p(1-p)}{n} }](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%7D)
Where p is the population mean that is proportion of female students and n is the sample size.
![\sigma = \sqrt{\frac{0.60(1-0.60)}{50} }\\\\\sigma = \sqrt{\frac{0.60(0.40)}{50} }\\\\\sigma = \sqrt{\frac{0.24}{50} }\\\\\sigma = \sqrt{0.0048} }\\\\\sigma = 0.069](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B%5Cfrac%7B0.60%281-0.60%29%7D%7B50%7D%20%7D%5C%5C%5C%5C%5Csigma%20%3D%20%5Csqrt%7B%5Cfrac%7B0.60%280.40%29%7D%7B50%7D%20%7D%5C%5C%5C%5C%5Csigma%20%3D%20%5Csqrt%7B%5Cfrac%7B0.24%7D%7B50%7D%20%7D%5C%5C%5C%5C%5Csigma%20%3D%20%5Csqrt%7B0.0048%7D%20%7D%5C%5C%5C%5C%5Csigma%20%3D%20%200.069)
Therefore, the standard deviation of the sampling distribution is 0.069.
There are 6 pints 14 ounces left. But with you need in quarts and ounces it would be <span>3 quarts 14 ounces.
Hope this helps!</span>
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