Distance from P to the x-axis = 2x distance from P to the yz-plane
<span>Distance to the x-axis of a point P=(x,y,z) is (y^2+z^2)^1/2 </span>
<span>Distance to the yz-plane of a point P=(x,y,z) is x </span>
<span>So your equation is: </span>
<span>(y^2+z^2)^1/2 = 2x </span>
<span>=> y^2 + z^2 = 4x^2 </span>
<span>=> y^2 + z^2 - 4x^2 = 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
</span>
Answer:
yea sure
Step-by-step explanation:
<h3>Answer: A) 2</h3>
=====================================================
Work Shown:
u(50654) = 5+0+6+5+4 = 20
u(20) = 2+0 = 2
u(50654) = 2
We want to find all possible values of m such that u(m) = 2 and also m is some two-digit integer.
-----
Possible values of m are: m = 11, m = 20
u(m) = u(11) = 1+1 = 2
u(m) = u(20) = 2+0 = 2
and that's it. There are no other ways to have two positive integers add up to 2.
I don't know I don't know I don't know I don't know I don't know I don't know I don't know
Answer: points in original figure (-6, 2)
Points in final figure (6, 2)
Step-by-step explanation:
First reflect the figure over the y axis. Then you can see that y is still 2 and that d has now become positive 6
Put those values in as (6,2) for the final figure
