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dalvyx [7]
3 years ago
13

isabella has found that she stays the most fit by running variouse dinstances and terrains through out the week. On mondays she

runs 2.5 miles, on tuesdays 4.6 miles, on thursdays 6.75 miles, and on saturdays 4.8 miles. What is the  average distance isabella runs on each of the days that she runs? round to the nearest hunfreth of a mile
Mathematics
1 answer:
den301095 [7]3 years ago
6 0
Monday . . . . . 2.5 miles
Tuesday . . . . . 4.6
Thursday . . . . 6.75
Saturday . . . . . 4.8

Total = 18.65 miles
Days per week = 4

Average miles per running day = 18.65/4 = 4.6625 miles

Rounded to the nearest 0.01 = 4.66 miles per running day
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Step-by-step explanation:

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4 0
3 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


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3 years ago
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