Answer:
8x²- x -8
Step-by-step explanation:
The question is not well written. I guess what you mean is:
Subtract -2x^2+4x-1 ( minus 2x squared plus 4x minus 1) from 6x^2+3x-9 (6x squared plus 3x minus 9).
To subtract -2x^2+4x-1 from 6x^2+3x-9, that is
6x^2+3x-9 - (-2x^2+4x-1). This can be written as
6x²+3x-9 - (-2x²+4x-1)
Now, opening the bracket, we will get
6x²+3x-9 +2x²-4x+1
Then, collecting like terms, we get
6x²+2x²+3x-4x-9+1
6x²+2x² = 8x²
3x-4x = -x
-9+1 = -8
∴6x²+2x²+3x-4x-9+1 becomes
8x²-x -8
The answer is 8x²-x -8.
Answer:
Step-by-step explanation:
Given
Required
This is calculated as:
Since, it is a probability with replacement, we have:
So, we have:
If we expand bx to jx and kx we have:
5y^2-2y-7
5y^2-7y+5y-7 then factor...
y(5y-7)+1(5y-7)
(y+1)(5y-7)
So the other factor is:
(y+1)
Answer: (4y - 3)(3x - 2)
Step-by-step explanation: Factor the polynomial.
Hope this helps! :) ~Zane
Answer:
x = 0
y = 2
Step-by-step explanation:
3x + 9y = 18 ---------eqn 1
y = x + 2---------eqn 2
Substitute eqn 2 into eqn 1, for the value of y
3x + 9( x + 2) = 18
3x + 9x + 18 = 18
12x + 18 = 18
12x = 18 -18
12x = 0
Divide both sides by 12 , to get the value of x.
12x/ 12 = 0/12
x = 0
Substitute x = 0 into eqn 2
y = x + 2
y = 0 +2
y = 2
Hint: to confirm the values
x = 0
y = 2
Let's take eqn 1 ,
3x + 9y = 18
3(0) + 9(2)
= 0 + 18
= 18
Correct
Let's take eqn 2
y = x + 2
Let's find y
y = 0 + 2
y = 2
Correct too
